php 从php中的文件夹中获取所有图像
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/17122218/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
get all the images from a folder in php
提问by Sksudip
I am using WordPress. I have an image folder like mytheme/images/myimages.
我正在使用 WordPress。我有一个像mytheme/images/myimages.
I want to retrieve all the images name from the folder myimages
我想从文件夹中检索所有图像名称 myimages
Please advice me, how can I get images name.
请给我建议，我怎样才能得到图像名称。
回答by sharif2008
try this
尝试这个
$directory = "mytheme/images/myimages";
$images = glob($directory . "/*.jpg");
foreach($images as $image)
{
echo $image;
}
回答by zur4ik
you can do it simply with PHP opendirfunction.
您可以简单地使用 PHPopendir函数来完成。
example:
例子：
$handle = opendir(dirname(realpath(__FILE__)).'/pictures/');
while($file = readdir($handle)){
if($file !== '.' && $file !== '..'){
echo '<img src="pictures/'.$file.'" border="0" />';
}
}
回答by Shafiqul Islam
when you want to get all image from folder then use glob()built in function which help to get all image . But when you get all then sometime need to check that all is valid so in this case this code help you. this code will also check that it is image
当您想从文件夹中获取所有图像时，请使用glob()内置函数来帮助获取所有图像。但是，当您获得所有内容时，有时需要检查所有内容是否有效，因此在这种情况下，此代码可以帮助您。此代码还将检查它是否是图像
$all_files = glob("mytheme/images/myimages/*.*");
for ($i=0; $i<count($all_files); $i++)
{
$image_name = $all_files[$i];
$supported_format = array('gif','jpg','jpeg','png');
$ext = strtolower(pathinfo($image_name, PATHINFO_EXTENSION));
if (in_array($ext, $supported_format))
{
echo '<img src="'.$image_name .'" alt="'.$image_name.'" />'."<br /><br />";
} else {
continue;
}
}
for more information
想要查询更多的信息
回答by Lorenz
$dir = "mytheme/images/myimages";
$dh = opendir($dir);
while (false !== ($filename = readdir($dh))) {
$files[] = $filename;
}
$images=preg_grep ('/\.jpg$/i', $files);
Very fast because you only scan the needed directory.
非常快，因为您只扫描所需的目录。
回答by Ajay Kumar
Here is my some code
这是我的一些代码
$dir = '/Images';
$ImagesA = Get_ImagesToFolder($dir);
print_r($ImagesA);
function Get_ImagesToFolder($dir){
$ImagesArray = [];
$file_display = [ 'jpg', 'jpeg', 'png', 'gif' ];
if (file_exists($dir) == false) {
return ["Directory \'', $dir, '\' not found!"];
}
else {
$dir_contents = scandir($dir);
foreach ($dir_contents as $file) {
$file_type = pathinfo($file, PATHINFO_EXTENSION);
if (in_array($file_type, $file_display) == true) {
$ImagesArray[] = $file;
}
}
return $ImagesArray;
}
}
回答by Philipp
This answer is specific for WordPress:
此答案特定于 WordPress：
$base_dir = trailingslashit( get_stylesheet_directory() );
$base_url = trailingslashit( get_stylesheet_directory_uri() );
$media_dir = $base_dir . 'yourfolder/images/';
$media_url = $hase_url . 'yourfolder/images/';
$image_paths = glob( $media_dir . '*.jpg' );
$image_names = array();
$image_urls = array();
foreach ( $image_paths as $image ) {
$image_names[] = str_replace( $media_dir, '', $image );
$image_urls[] = str_replace( $media_dir, $media_url, $image );
}
// --- You now have:
// $image_paths ... list of absolute file paths
// e.g. /path/to/wordpress/wp-content/uploads/yourfolder/images/sample.jpg
// $image_urls ... list of absolute file URLs
// e.g. http://example.com/wp-content/uploads/yourfolder/images/sample.jpg
// $image_names ... list of filenames only
// e.g. sample.jpg
Here are some other settings that will give you images from other places than the child theme. Just replace the first 2 lines in above code with the version you need:
以下是一些其他设置，可以为您提供来自子主题以外其他地方的图像。只需用您需要的版本替换上面代码中的前两行：
From Uploads directory:
从上传目录：
// e.g. /path/to/wordpress/wp-content/uploads/yourfolder/images/sample.jpg
$upload_path = wp_upload_dir();
$base_dir = trailingslashit( $upload_path['basedir'] );
$base_url = trailingslashit( $upload_path['baseurl'] );
From Parent-Theme
从父主题
// e.g. /path/to/wordpress/wp-content/themes/parent-theme/yourfolder/images/sample.jpg
$base_dir = trailingslashit( get_template_directory() );
$base_url = trailingslashit( get_template_directory_uri() );
From Child-Theme
从儿童主题
// e.g. /path/to/wordpress/wp-content/themes/child-theme/yourfolder/images/sample.jpg
$base_dir = trailingslashit( get_stylesheet_directory() );
$base_url = trailingslashit( get_stylesheet_directory_uri() );
回答by Site Baker
Check if exist, put all files in array, preg grep all JPG files, echo new array For all images could try this:
检查是否存在，将所有文件放入数组，preg grep 所有 JPG 文件，回显新数组对于所有图像可以尝试这个：
$images=preg_grep('/\.(jpg|jpeg|png|gif)(?:[\?\#].*)?$/i', $files);
if ($handle = opendir('/path/to/folder')) {
while (false !== ($entry = readdir($handle))) {
$files[] = $entry;
}
$images=preg_grep('/\.jpg$/i', $files);
foreach($images as $image)
{
echo $image;
}
closedir($handle);
}
回答by alex
//path to the directory to search/scan
$directory = "";
//echo "$directory"
//get all files in a directory. If any specific extension needed just have to put the .extension
//$local = glob($directory . "*");
$local = glob("" . $directory . "{*.jpg,*.gif,*.png}", GLOB_BRACE);
//print each file name
echo "<ul>";
foreach($local as $item)
{
echo '<li><a href="'.$item.'">'.$item.'</a></li>';
}
echo "</ul>";
回答by Ajmal Tk
You can simply show your actual image directory(less secure). By just 2 line of code.
您可以简单地显示您的实际图像目录（不太安全）。只需 2 行代码。
$dir = base_url()."photos/";
echo"<a href=".$dir.">Photo Directory</a>";
