从 Swift 在 iOS 上生成 UUID
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Generate a UUID on iOS from Swift
提问by zacjordaan
In my iOS Swift app I want to generate random UUID (GUID) strings for use as a table key, and this snippet appearsto work:
在我的 iOS Swift 应用程序中，我想生成随机 UUID ( GUID) 字符串以用作表键，并且此代码段似乎有效：
let uuid = CFUUIDCreateString(nil, CFUUIDCreate(nil))
Is this safe?
这安全吗？
Or is there perhaps a better (recommended) approach?
或者是否有更好的（推荐的）方法？
回答by Ahmed Al Hafoudh
Try this one:
试试这个：
let uuid = NSUUID().uuidString
print(uuid)
Swift 3/4/5
迅捷 3/4/5
let uuid = UUID().uuidString
print(uuid)
回答by James Frost
回答by Celil Bozkurt
For Swift 4;
对于Swift 4;
let uuid = NSUUID().uuidString.lowercased()
回答by Scott H
For Swift 3, many Foundationtypes have dropped the 'NS' prefix, so you'd access it by UUID().uuidString.
对于 Swift 3，许多Foundation类型都删除了“NS”前缀，因此您可以通过UUID().uuidString.
回答by SwiftDeveloper
Also you canuse it lowercaseunder below
你can也可以lowercase在下面使用它
let uuid = NSUUID().UUIDString.lowercaseString
print(uuid)
Output
输出
68b696d7-320b-4402-a412-d9cee10fc6a3
68b696d7-320b-4402-a412-d9cee10fc6a3
Thank you !
谢谢 ！
回答by iAleksandr
Each time the same will be generated:
每次都会生成相同的：
if let uuid = UIDevice.current.identifierForVendor?.uuidString {
print(uuid)
}
Each time a new one will be generated:
每次都会生成一个新的：
let uuid = UUID().uuidString
print(uuid)
