如何在 Java 中显示 N x N 随机数矩阵？
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How Can I Display a N x N Matrix of Random Numbers in Java?
提问by Tamara JQ
I'm trying to create a matrix of random double numbers. The matrix must be of size n x n and all numbers must be between 1 and 100. I've been trying to sort it out for ages now and I know it must be something so simple (as it usually is).
我正在尝试创建一个随机双数矩阵。矩阵的大小必须为 nxn，并且所有数字都必须在 1 到 100 之间。我多年来一直试图对其进行排序，我知道它一定很简单（通常如此）。
Here is my code:
这是我的代码：
public static void main(String[] args) {
PrintRandomGraph(RandomArray(4));
}
private static double[] RandomArray(int n) {
double[] randomArray = new double[n];
double[][] randomMatrix = new double [n][n];
Random rand = new Random();
rand.setSeed(System.currentTimeMillis());
for (int i = 0; i < n; i++) {
Integer r = rand.nextInt()% 100;
randomArray[i] = Math.abs(r);
for (int j = 0; j < n; j++) {
Arrays.fill(randomMatrix, i, i+1, randomArray);
}
}
return randomArray;
}
private static void PrintRandomGraph(double[] inputArray) {
int n = inputArray.length;
double[] showArray = new double[n];
double[][] showMatrix = new double [n][n];
for (int j = 0; j < n; j++) {
for (int i = 0; i < n; i++) {
double r = inputArray[i];
showArray[i] = r;
Arrays.fill(showMatrix, i, i+1, showArray);
}
}
System.out.println(Arrays.deepToString(showMatrix));
}
When I run the code I get a random array repeated n times like :
当我运行代码时，我得到一个重复 n 次的随机数组，例如：
[[63.0, 97.0, 64.0, 75.0], [63.0, 97.0, 64.0, 75.0], [63.0, 97.0, 64.0, 75.0], [63.0, 97.0, 64.0, 75.0]]
[[63.0, 97.0, 64.0, 75.0], [63.0, 97.0, 64.0, 75.0], [63.0, 97.0, 64.0, 75.0], [63.0, 97.0, 64.0], 750
I think I need to go back to the top of the for loop and add the new array...? Please help =(
我想我需要回到 for 循环的顶部并添加新数组...？请帮忙=（
Any help is much appreciated. Thank you.
任何帮助深表感谢。谢谢你。
采纳答案by Tamara JQ
Hi all this provides the answer I was looking for
嗨，这一切提供了我一直在寻找的答案
private static double[][] RandomArray(int n) {
double[][] randomMatrix = new double [n][n];
double[] randomArray = new double [n];
Random rand = new Random();
rand.setSeed(System.currentTimeMillis());
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
Integer r = rand.nextInt()% 100;
randomMatrix[i][j] = Math.abs(r);
}
}
return randomMatrix;
}
public static void main(String[] args){
//PrintRandomGraph(RandomArray(5));
System.out.println(Arrays.deepToString(RandomArray(5)));
}
回答by npinti
Did you try something like this:
你有没有尝试过这样的事情：
private static double[][] RandomArray(int n) {
double[][] randomMatrix = new double [n][n];
Random rand = new Random();
rand.setSeed(System.currentTimeMillis());
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
Integer r = rand.nextInt()% 100;
randomMatrix[i][j] = Math.abs(r);
}
}
return randomMatrix;
}
to Print the graph:
打印图形：
public void printGraph(double[][] array, int n) {
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
System.out.println(array[i][j]);
}
}
}
To Print Graph with Square brackets:
用方括号打印图形：
public void printGraph(double[][] array, int n) {
for (int i = 0; i < n; i++) {
System.out.print(" [ ");
for (int j = 0; j < n; j++) {
System.out.print(array[i][j]);
}
//Put println instead of print here to have each row in a new line
System.out.print(" ]");
}
}
Also, this seems a lot like homework, if it is, please tag it like so :)
另外，这看起来很像家庭作业，如果是，请像这样标记它:)
