Java 使用 JodaTime 计算两个日期之间的月份,记住年份
声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow
原文地址: http://stackoverflow.com/questions/19677739/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Calculate months between two dates keeping year in mind using JodaTime
提问by Abhishek Singh
I am using this code to calculate no of months between input pastdate and currentdate. It uses JodaTime
我正在使用此代码来计算输入过去日期和当前日期之间的月数。它使用 JodaTime
LocalDate date1 = new LocalDate(installmentStartDate2);
LocalDate date2 = new LocalDate(new java.util.Date());
PeriodType monthDay = PeriodType.yearMonthDayTime();
Period difference = new Period(date1, date2, monthDay);
int months = difference.getMonths();
return months + 1;
Now when i enter 1 jan 2013 i get 10 as answer. But the problem is get 10 even when i enter 1 jan 2012.
现在,当我输入 2013 年 1 月 1 日时,我得到 10 作为答案。但问题是即使我进入 2012 年 1 月 1 日也得到 10。
So that means while calculation it doesn't considers year.
所以这意味着在计算时不考虑年份。
What can i do to get correct answer i.e., 22 when i enter 1 jan 2012.
当我进入 2012 年 1 月 1 日时,我该怎么做才能得到正确的答案,即 22。
Can JodaTime do that ? If yes ? How ? If not ? Any other approach ?
JodaTime 能做到吗?如果是 ?如何 ?如果不 ?还有其他方法吗?
采纳答案by chillworld
Your code is almost correct.
你的代码几乎是正确的。
You can change :
你可以改变 :
PeriodType monthDay = PeriodType.yearMonthDayTime();
to :
到 :
PeriodType monthDay = PeriodType.months();
and it will work also.
它也会起作用。
回答by Jon Skeet
You're asking for the difference in years, months and days - so you're getting back 1 year, 10 months and 29 days.
您要求的是年、月和日的差异 - 所以您要返回 1 年、10 个月和 29 天。
Just use:
只需使用:
int months = Months.monthsBetween(date1, date2).getMonths();
Or if you really want to use new Period
and perhaps get days as well you can use:
或者,如果您真的想使用new Period
并且可能还需要几天,您可以使用:
PeriodType monthDay = PeriodType.yearMonthDayTime().withYearsRemoved();
Period difference = new Period(date1, date2, monthDay);
You could just use PeriodType.months()
, but if you're genuinely only interested in the months, I'd use the first snippet above to do it all in a single short-ish statement.
您可以只使用PeriodType.months()
,但如果您真的只对月份感兴趣,我会使用上面的第一个片段在一个简短的语句中完成所有操作。
回答by Gabber
Joda time is good way to dealing with this problem
Joda 时间是处理这个问题的好方法
Create a joda time date object
创建一个 joda 时间日期对象
DateTime startDate = DateTime.parse("1970-01-01", DateTimeFormat.forPattern("yyyy-MM-dd"))
DateTime endDate = DateTime.parse("2015-02-25", DateTimeFormat.forPattern("yyyy-MM-dd"))
Difference between two dates in days
两个日期之间的天数差异
int days = Days.daysBetween(startDate, endDate).getDays()
Difference between two dates in months
两个日期之间的月差
int months = Months.monthsBetween(startDate.withDayOfMonth(1), endDate.withDayOfMonth(1)).getMonths()
Difference between two dates in years
两个日期之间的年差
int years = Years.yearsBetween(startDate, endDate).getYears();
回答by android developer
I suggest using this:
我建议使用这个:
ChronoUnit.MONTHS.between(earlierDate,date)