C# 将字符串转换为小数点后两位

Convert string to 2 decimal place

提问by william007

I have a string (confirm to be of decimal expression) 0.4351242134

我有一个字符串（确认是十进制表达式）0.4351242134

I want to convert to a string with two decimal place 0.44

我想转换为带有两位小数的字符串 0.44

How should I do in C#?

我应该如何在 C# 中做？

采纳答案by Ilya Ivanov

var probablyDecimalString = "0.4351242134";
decimal value;
if (Decimal.TryParse(probablyDecimalString , out value))
    Console.WriteLine ( value.ToString("0.##") );
else
    Console.WriteLine ("not a Decimal");

回答by Zak

float f = float.Parse("0.4351242134");
Console.WriteLine(string.Format("{0:0.00}", f));

See thisfor string.Format.

有关string.Format 的信息，请参阅此内容。

回答by Mharlin

var d = decimal.Parse("0.4351242134");
Console.WriteLine(decimal.Round(d, 2));

回答by Renatas M.

Well I would do:

好吧，我会这样做：

var d = "0.4351242134";
Console.WriteLine(decimal.Parse(d).ToString("N2"));

回答by Rohit

Would this help

这有帮助吗

double ValBefore= 0.4351242134;
double ValAfter= Math.Round(ValBefore, 2, MidpointRounding.AwayFromZero); //Rounds"up"

回答by Enkode

float myNumber = float.Parse("0.4351242134");
Console.WriteLine(string.Format("{0:f2}", myNumber ));

https://msdn.microsoft.com/en-us/library/s8s7t687.aspx

https://msdn.microsoft.com/en-us/library/s8s7t687.aspx