C++ ascii 字符 255 是不可见字符还是空格？
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Is ascii character 255 an invisible character or space?
提问by Dljcali
I am writing some code to print overlapping ASCII character objects and I want some to be invisible instead of the typical " " white space character. Would this solve it?
我正在编写一些代码来打印重叠的 ASCII 字符对象，我希望一些不可见，而不是典型的“”空白字符。这能解决吗？
cout << char(255);
回答by lou
In the most common extended 8-bit ASCII tables 255 is the '?' symbol (Latin small letter y with diaeresis). The space character is decimal value 32. So what you are searching for is probably:
在最常见的扩展 8 位 ASCII 表中，255 是“？” 符号（带分音符的拉丁小写字母 y）。空格字符是十进制值 32。所以你要搜索的可能是：
cout << char(32);
回答by FlameBlazer
I guess you mean when you press ALT+255.
我猜你的意思是当你按下 ALT+255 时。
And no ALT+255 is not the same as a space.
并且没有 ALT+255 不等于空格。
Here is a table of the characters values.
这是字符值的表。
Char ????????Dec Hex Oct
字符 ????????Dec 十六进制 十月
SPACE ?????32 ??20 ??40
空间 ???32 ??20 ??40
ALT+255??160 ?A0 ?240
ALT+255??160 ?A0 ?240
I don't know much C++ but maybe it is
我不太了解 C++，但也许是
cout << char(160);
