php 获取所有mysql选定的行到一个数组中
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Get all mysql selected rows into an array
提问by Gandalf
I am wondering if there a function in php that can allow me put all my selected data in an array .Currently i am using mysql_fetch_array and as i have read in the manual,that function won't fetch every record in the table.
我想知道 php 中是否有一个函数可以让我将所有选定的数据放入一个数组中。目前我正在使用 mysql_fetch_array 并且正如我在手册中所阅读的那样，该函数不会获取表中的每条记录。
$result = mysql_query("SELECT * FROM $tableName");
$array = mysql_fetch_array($result);
echo json_encode($array);
回答by Mike Mackintosh
I would suggest the use of MySQLi or MySQL PDO for performance and security purposes, but to answer the question:
为了性能和安全目的，我建议使用 MySQLi 或 MySQL PDO，但要回答这个问题：
while($row = mysql_fetch_assoc($result)){
$json[] = $row;
}
echo json_encode($json);
If you switched to MySQLi you could do:
如果您切换到 MySQLi，您可以执行以下操作：
$query = "SELECT * FROM table";
$result = mysqli_query($db, $query);
$json = mysqli_fetch_all ($result, MYSQLI_ASSOC);
echo json_encode($json );
回答by John Conde
Loop through the results and place each one in an array
use
mysqli_fetch_all()to get them all at one time
循环遍历结果并将每个结果放在一个数组中
用于
mysqli_fetch_all()一次全部获取
回答by Brandon Ferrara
You could try:
你可以试试：
$rows = array();
while($row = mysql_fetch_array($result)){
array_push($rows, $row);
}
echo json_encode($rows);
回答by dev4092
$name=array();
while($result=mysql_fetch_array($res)) {
$name[]=array('Id'=>$result['id']);
// here you want to fetch all
// records from table like this.
// then you should get the array
// from all rows into one array
}
回答by Dragooon
you can call mysql_fetch_array() for no_of_row time
您可以在 no_of_row 时间内调用 mysql_fetch_array()
