C# 如何以编程方式向datagridview添加新行
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How to add a new row to datagridview programmatically
提问by LK Yeung
if add row to DataTable
如果添加行 DataTable
DataRow row = datatable1.NewRow();
row["column2"]="column2";
row["column6"]="column6";
datatable1.Rows.Add(row);
How about DataGridView??
怎么样DataGridView??
采纳答案by Habib
You can do:
你可以做:
DataGridViewRow row = (DataGridViewRow)yourDataGridView.Rows[0].Clone();
row.Cells[0].Value = "XYZ";
row.Cells[1].Value = 50.2;
yourDataGridView.Rows.Add(row);
or:
或者:
DataGridViewRow row = (DataGridViewRow)yourDataGridView.Rows[0].Clone();
row.Cells["Column2"].Value = "XYZ";
row.Cells["Column6"].Value = 50.2;
yourDataGridView.Rows.Add(row);
Another way:
其它的办法:
this.dataGridView1.Rows.Add("five", "six", "seven","eight");
this.dataGridView1.Rows.Insert(0, "one", "two", "three", "four");
From: http://msdn.microsoft.com/en-us/library/system.windows.forms.datagridview.rows.aspx
来自:http: //msdn.microsoft.com/en-us/library/system.windows.forms.datagridview.rows.aspx
回答by Mahmoud Gamal
Like this:
像这样:
dataGridView1.Columns[0].Name = "column2";
dataGridView1.Columns[1].Name = "column6";
string[] row1 = new string[] { "column2 value", "column6 value" };
dataGridView1.Rows.Add(row1);
Or you need to set there values individually use the propery .Rows(), like this:
或者您需要使用属性单独设置值.Rows(),如下所示:
dataGridView1.Rows[1].Cells[0].Value = "cell value";
回答by Defkon1
Adding a new row in a DGV with no rows with Add()raises SelectionChangedevent before you can insert any data (or bind an object in Tag property).
在插入任何数据(或在 Tag 属性中绑定对象)之前,使用Add()在没有行的 DGV 中添加新行会引发SelectionChanged事件。
Create a clone row from RowTemplateis safer imho:
从RowTemplate创建一个克隆行更安全恕我直言:
//assuming that you created columns (via code or designer) in myDGV
DataGridViewRow row = (DataGridViewRow) myDGV.RowTemplate.Clone();
row.CreateCells(myDGV, "cell1", "cell2", "cell3");
myDGV.Rows.Add(row);
回答by Jizakh
Like this:
像这样:
var index = dgv.Rows.Add();
dgv.Rows[index].Cells["Column1"].Value = "Column1";
dgv.Rows[index].Cells["Column2"].Value = 5.6;
//....
回答by Anders
If the grid is bound against a DataSet / table its better to use a BindingSource like
如果网格绑定到数据集/表,最好使用 BindingSource 之类的
var bindingSource = new BindingSource();
bindingSource.DataSource = dataTable;
grid.DataSource = bindingSource;
//Add data to dataTable and then call
bindingSource.ResetBindings(false)
回答by silent tone
If you need to manipulate anything aside from the Cell Value string such as adding a Tag, try this:
如果您需要操作除 Cell Value 字符串之外的任何内容,例如添加标签,请尝试以下操作:
DataGridViewRow newRow = (DataGridViewRow)mappingDataGridView.RowTemplate.Clone();
newRow.CreateCells(mappingDataGridView);
newRow.Cells[0].Value = mapping.Key;
newRow.Cells[1].Value = ((BusinessObject)mapping.Value).Name;
newRow.Cells[1].Tag = mapping.Value;
mappingDataGridView.Rows.Add(newRow);
回答by Sherif Hamdy
An example of copy row from dataGridView and added a new row in The same dataGridView:
从 dataGridView 复制行并在同一 dataGridView 中添加新行的示例:
DataTable Dt = new DataTable();
Dt.Columns.Add("Column1");
Dt.Columns.Add("Column2");
DataRow dr = Dt.NewRow();
DataGridViewRow dgvR = (DataGridViewRow)dataGridView1.CurrentRow;
dr[0] = dgvR.Cells[0].Value;
dr[1] = dgvR.Cells[1].Value;
Dt.Rows.Add(dR);
dataGridView1.DataSource = Dt;
回答by Overdrive77
Lets say you have a datagridview that is not bound to a dataset and you want to programmatically populate new rows...
假设您有一个未绑定到数据集的数据网格视图,并且您想以编程方式填充新行...
Here's how you do it.
这是你如何做到的。
// Create a new row first as it will include the columns you've created at design-time.
int rowId = dataGridView1.Rows.Add();
// Grab the new row!
DataGridViewRow row = dataGridView1.Rows[rowId];
// Add the data
row.Cells["Column1"].Value = "Value1";
row.Cells["Column2"].Value = "Value2";
// And that's it! Quick and painless... :o)
回答by DotNET
Consider a Windows Application and using Button Click Event put this code in it.
考虑一个 Windows 应用程序并使用按钮单击事件将此代码放入其中。
dataGridView1.Rows
.Add(new object[] { textBox1.Text, textBox2.Text, textBox3.Text });
回答by Rei Salazar
//Add a list of BBDD
var item = myEntities.getList().ToList();
//Insert a new object of type in a position of the list
item.Insert(0,(new Model.getList_Result { id = 0, name = "Coca Cola" }));
//List assigned to DataGridView
dgList.DataSource = item;

