Python 您可以将列表附加到字典中吗？
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Can you append a list to a dictionary?
提问by Rutwb2
So i need to create a list which will save the users inputs (a name and their 3 scores) and that will then append this information to one of 3 files. I tried doing this by appending the data to a list and then the list to a dictionary but this doesn't seem to work. I am really new to python so would really appreciate any help. This is my code so far;
所以我需要创建一个列表来保存用户输入（一个名字和他们的 3 个分数），然后将此信息附加到 3 个文件之一。我尝试通过将数据附加到列表然后将列表附加到字典来做到这一点，但这似乎不起作用。我对python真的很陌生，所以非常感谢任何帮助。到目前为止，这是我的代码；
dict1 = {}
dict2 = {}
dict3 = {}
list1 = []
list2 =[]
list3 =[]
def main():
name= input ('What is your name?')
for i in range(0,3)
score = input("Enter your score: ")
clss =input('which class?')
if clss==1:
list1.append (name, score)
elif clss==2:
list2.append (name, score)
elif clss==3:
list3.append (name, score)
Here i want to append the list to one of 3 dictionaries depending on the class
在这里，我想根据课程将列表附加到 3 个词典之一
def loop():
x=input('Do you want to make an entry?')
if x=='Yes':
main()
elif x=='No':
sys.exit(0)
loop()
采纳答案by Teemu Kurppa
You need to have lists in dictionary to be able to append to them. You can do something like:
您需要在字典中有列表才能附加到它们。您可以执行以下操作：
scores = {"class1": [], "class2": [], "class3": []}
def main():
name= input ('What is your name?')
for i in range(0,3)
score = input("Enter your score: ")
clss =input('which class?')
if clss==1:
scores["class1"].append({"name": name, "score": score})
elif clss==2:
scores["class2"].append({"name": name, "score": score})
elif clss==3:
scores["class3"].append({"name": name, "score": score})
print scores
回答by Aleksander Monk
Have you tried to use defaultdict ? Example from the python docs:
您是否尝试过使用 defaultdict ？来自 python 文档的示例：
>>> s = 'mississippi'
>>> d = defaultdict(int)
>>> for k in s:
... d[k] += 1
...
>>> d.items()
[('i', 4), ('p', 2), ('s', 4), ('m', 1)]
You can see another example of using defaultdict here
您可以在此处查看使用 defaultdict 的另一个示例
回答by Katpoes
dictionary = {i:x for i,x in enumerate([['List', 'one'],['List', 'two']])}
A somewhat different approach would be this, I'm unsure if this is what you mean but I tried my best understanding. I also tried keeping it as simple as possible.
一种稍微不同的方法是这样，我不确定这是否是您的意思，但我已尽力理解。我也尽量保持简单。
d = {}
while True:
# Ask the user to make a new entry.
raw = raw_input('Make a new entry?')
if raw.lower() in ['y', 'yes']:
# Ask the users name.
name = raw_input('Your name?')
# Create new entrypoint in the dictionary containing a empty list bound to the name
d[name] = []
for score in range(3):
# Ask the user for three scores
d[name].append(raw_input('Enter a new score: '))
# If the input doesn't match you break out of the loop.
else:
break
# You can at any time print the contents of the dictionary.
# print d
