Javascript href中调用ajax请求函数

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时间:2020-08-23 04:04:27  来源:igfitidea点击:

Calling Ajax request function in href

javascriptjqueryajaxhtml

提问by Lotus91

I have an href in an html page and i have an AJAX request in a method in a javascript file.

我在一个 html 页面中有一个 href 并且我在一个 javascript 文件中的一个方法中有一个 AJAX 请求。

When clicking on href i want to call the JS function and I am treating the response to add it to the second html page which will appear

单击 href 时,我想调用 JS 函数,我正在处理响应以将其添加到将出现的第二个 html 页面

function miniReport(){

    alert('TEST');

   var client_account_number = localStorage.getItem("numb");

   var request = $.ajax({
        url: server_url + '/ws_report',
        timeout:30000,
        type: "POST",
        data: {client_language: client_language, PIN_code:pin,client_phone:number}
    });
    request.done(function(msg) {
        //alert(JSON.stringify(msg));

    });
    if (msg.ws_resultat.result_ok==true)
    {
        alert('success!');
        window.open("account_details.html");

    }

    request.error(function(jqXHR, textStatus)
    {
       //MESSAGE
    });

}

I tried with <a href="#" onclick="miniReport()"></a>, and also to write the function with $('#idOfHref').click(function(){});not working.

我尝试使用<a href="#" onclick="miniReport()"></a>, 并且还编写了不起作用的函数$('#idOfHref').click(function(){});

All I can see is the alert TEST and then nothing happens. I checked several posts here but nothing works for me.

我只能看到警报 TEST,然后什么也没有发生。我在这里查看了几篇文章,但没有任何内容对我有用。

回答by Vikrant

Function can be corrected as,

函数可以修正为,

function miniReport(){
    alert('TEST');    
   var client_account_number = localStorage.getItem("numb");

   $.ajax({
        url: server_url + '/ws_report',
        timeout:30000,
        type: "POST",
        data: {"client_language": client_language, "PIN_code":pin,"client_phone":number},
        success : function(msg) {
        //alert(JSON.stringify(msg));
            if (msg.ws_resultat.result_ok == true)
            {
                alert('success!');
                window.open("account_details.html");    
            }
        },
        error: function(jqXHR, textStatus)
        {
           alert('Error Occured'); //MESSAGE
        }
     }
 });

1. No need to assign ajax call to a variable,
2. Your further work should be in Success part of AJAXrequest, as shown above.

1.无需将ajax调用分配给变量,
2.您的进一步工作应该在AJAX请求的成功部分,如上所示。

回答by gon250

It's a bad practice use an onclick()so the proper way to do this is:

使用 an 是一种不好的做法,onclick()因此执行此操作的正确方法是:

Fiddle

小提琴

$(document).ready(function(){
   $('#mylink').on('click', function(){
      alert('onclick is working.');
      miniReport(); //Your function 
   });
});

function miniReport(){
     var client_account_number = localStorage.getItem('numb');
     $.ajax({
        url: server_url + '/ws_report',
        timeout:30000,
        type: "POST",
        data: {
            'client_language': client_language, 
            'PIN_code': pin,
            'client_phone': number
       },
        success: function(msg){
            if (msg.ws_resultat.result_ok==true)
            {
                alert('success!');
                window.open("account_details.html");
            }
        },
            error: function(jqXHR, textStatus)
          {
           //Manage your error.   
          }
    });
}

Also you have some mistakes in your ajax request. So I hope it's helps.

您的 ajax 请求中也有一些错误。所以我希望它有帮助。

回答by Neelesh

Rectified version of your code with document .ready

使用文档 .ready 修正您的代码版本

    $(document).ready(function(){
    $("#hrefid").click(function(){ // your anchor tag id if not assign any id 

           var client_account_number = localStorage.getItem("numb");
           $.ajax({
            url: server_url + '/ws_report',
            timeout:30000,
            type: "POST",
data:{"client_language":client_language,"PIN_code":pin,"client_phone":number},
            success : function(msg) {

                if (msg.ws_resultat.result_ok == true)
                {
                   window.open("account_details.html");    
                }
                else 
                {
                  alert('some thing went wrong, plz try again');
                }
            }

         }
    });
    });