正则表达式只有空格 - javascript
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regex only spaces - javascript
提问by Marco
I need to filter a field composed of only spaces; something like:
我需要过滤一个仅由空格组成的字段；就像是：
if (word == /((\s)+)/ ) return 'no name'
but it doesn't work ... any other ideas? thank you for your ideas!
但它不起作用......还有其他想法吗？谢谢你的想法！
回答by Gabi Purcaru
You should use if(/^\s+$/.test(word)). (Notice the ^and $, without them the regex will hold for any string that has at least a space-like character)
你应该使用if(/^\s+$/.test(word)). （注意^and $，没有它们，正则表达式将适用于任何至少具有类似空格字符的字符串）
回答by René Baudisch
How about NOTchecking "word" by RegExp but using RegExp to replace all whitespaces and look what's left. If it's empty "word" is only composed by whitespaces:
如何不通过 RegExp 检查“单词”，而是使用 RegExp 替换所有空格并查看剩下的内容。如果它是空的“单词”仅由空格组成：
if (word.replace(/\s+/, "") === "") {
console && console.log("empty string found!");
return 'no name';
}
