Java 使用 HTTP 客户端为 JSON 列表发送和解析响应
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Sending and Parsing Response using HTTP Client for a JSON List
提问by Global Dictator
With in my java code, I need to send a http post request to a specific URL with 3 headers:
在我的 Java 代码中，我需要向具有 3 个标头的特定 URL 发送一个 http post 请求：
URL: http://localhost/something
Referer: http://localhost/something
Authorization: Basic (with a username and password)
Content-type: application/json
This returns a response with a JSON "key":"value" pair in it that I then need to parse somehow to store the key/value (Alan/72) in a MAP. The response is (when using SOAPUI or Postman Rest):
这将返回一个包含 JSON "key":"value" 对的响应，然后我需要以某种方式解析以将键/值 (Alan/72) 存储在 MAP 中。响应是（使用 SOAPUI 或 Postman Rest 时）：
{
"analyzedNames": [
{
"alternate": false
}
],
"nameResults": [
{
"alternate": false,
"givenName": "John",
"nameCategory": "PERSONAL",
"originalGivenName": "",
"originalSurname": "",
"score": 72,
"scriptType": "NOSCRIPT",
}
]
}
I can do this using SOAPUI or Postman Rest but how can I do this within Java as I'm getting an error:
我可以使用 SOAPUI 或 Postman Rest 来做到这一点，但是当我收到错误时，我该如何在 Java 中做到这一点：
****DEBUG main org.apache.http.impl.conn.DefaultClientConnection - Receiving response: HTTP/1.1 500 Internal Server Error****
My code is:
我的代码是：
public class NameSearch {
/**
* @param args
* @throws IOException
* @throws ClientProtocolException
*/
public static void main(String[] args) throws ClientProtocolException, IOException {
// TODO Auto-generated method stub
DefaultHttpClient defaultHttpClient = new DefaultHttpClient();
StringWriter writer = new StringWriter();
//Define a postRequest request
HttpPost postRequest = new HttpPost("http://127.0.0.1:1400/dispatcher/api/rest/search");
//Set the content-type header
postRequest.addHeader("content-type", "application/json");
postRequest.addHeader("Authorization", "Basic ZW5zYWRtaW46ZW5zYWRtaW4=");
try {
//Set the request post body
StringEntity userEntity = new StringEntity(writer.getBuffer().toString());
postRequest.setEntity(userEntity);
//Send the request; return the response in HttpResponse object if any
HttpResponse response = defaultHttpClient.execute(postRequest);
//verify if any error code first
int statusCode = response.getStatusLine().getStatusCode();
}
finally
{
//Important: Close the connect
defaultHttpClient.getConnectionManager().shutdown();
}
}
}
Any help (with some sample code including which libraries to import) will be most appreciated.
任何帮助（一些示例代码，包括要导入的库）将不胜感激。
THANKS
谢谢
采纳答案by Georgy Gobozov
Yes, you can do it with java
是的，你可以用java来做
You need apache HTTP client library http://hc.apache.org/and commons-io
您需要 apache HTTP 客户端库http://hc.apache.org/和 commons-io
HttpClient client = new DefaultHttpClient();
HttpPost post = new HttpPost("http://localhost/something");
post.setHeader("Referer", "http://localhost/something");
post.setHeader("Authorization", "Basic (with a username and password)");
post.setHeader("Content-type", "application/json");
// if you need any parameters
List<NameValuePair> urlParameters = new ArrayList<NameValuePair>();
urlParameters.add(new BasicNameValuePair("paramName", "paramValue"));
post.setEntity(new UrlEncodedFormEntity(urlParameters));
HttpResponse response = client.execute(post);
HttpEntity entity = response.getEntity();
Header encodingHeader = entity.getContentEncoding();
// you need to know the encoding to parse correctly
Charset encoding = encodingHeader == null ? StandardCharsets.UTF_8 :
Charsets.toCharset(encodingHeader.getValue());
// use org.apache.http.util.EntityUtils to read json as string
String json = EntityUtils.toString(entity, StandardCharsets.UTF_8);
JSONObject o = new JSONObject(json);
回答by Beno Arakelyan
I recommend http-requestbuilt on Apache HTTP API.
我推荐建立在 Apache HTTP API 上的http-request。
HttpRequest<String> httpRequest = HttpRequestBuilder.createPost(yourUri
new TypeReference<Map<String, List<Map<String, Object>>>>{})
.basicAuth(userName, password)
.addContentType(ContentType.APPLICATION_JSON)
.build();
public void send(){
ResponseHandler<String> responseHandler = httpRequest.executeWithBody(yourJsonData);
int statusCode = responseHandler.getStatusCode();
Map<String, List<Map<String, Object>>> response = responseHandler.get(); // Before calling the get () method, make sure the response is present: responseHandler.hasContent()
System.out.println(response.get("nameResults").get(0).get("givenName")); //John
}
I highly recommend reading the documentation before use.
我强烈建议在使用前阅读文档。
Note: You can create your custom type instead of Mapto parse response. See my answer here.
注意：您可以创建自定义类型而不是Map来解析响应。在这里看到我的答案。
