Javascript jQuery Ajax 成功函数参数
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jQuery Ajax success function parameters
提问by nullException
$.ajax({
type: "POST",
url: "contacts.php",
data: dataString,
cache: false,
success: function(data, status, settings)
{
alert(The request URL and DATA);
}
,
error: function(ajaxrequest, ajaxOptions, thrownError)
{
}
});
How can I alert the The request URL and DATA parameters inside the Success function?
如何提醒 Success 函数中的 The request URL 和 DATA 参数？
Thank You
谢谢你
回答by Alex K.
You can simply;
你可以简单地;
success: function(data, textStatus, jqXHR)
{
alert(this.data + "," + this.url);
}
回答by snostorm
Adapted from Alex K.'s answer, but using console.log instead:
改编自 Alex K. 的回答，但使用 console.log 代替：
success: function(data, textStatus, jqXHR)
{
console.log(this.data + "," + this.url);
}
This will output the data to the debugging console instead of a modal dialog.
这会将数据输出到调试控制台而不是模式对话框。
回答by ricsdeol
I needed return some data in sucess response like:
我需要在成功响应中返回一些数据，例如：
Action (Rais):
动作（Rais）：
def comment
comnent = AlarmComment.new alarm_id: params[:id],
user_id: current_user.id, comment: params[:comment]
if comnent.save
render json: comnent, status: :created
else
head status: :unprocessable_entity
end
end
My Ajax (Coffee)
我的阿贾克斯（咖啡）
$.ajax(
url: "/alarms/#{alarm_id}/comment/"
dataType: "json"
method: "POST",
data:
comment: user_comment
).done( ->
alert 'Comentário adicionado com sucesso'
).fail ->
alert 'Erro ao adicionar'
