javascript 替换某个点之前的所有文本
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Replace all text before a certain point
提问by UserIsCorrupt
$(function(){
var alphabet = "ABCDEFGHIJKLMNOPQRSTUVEXYZ";
var replaced = alphabet.replace(/(M).+$/,'');
$('body').text(replaced);
});
How can I make this go in the opposite direction, replacing Mand everything before it?
我怎样才能让它朝着相反的方向发展，替换M它之前的一切？
回答by VisioN
Use /^.+M/expression:
使用/^.+M/表达式：
$(function() {
var alphabet = "ABCDEFGHIJKLMNOPQRSTUVEXYZ";
var replaced = alphabet.replace(/^.+M/,'');
$('body').text(replaced);
});
DEMO:http://jsfiddle.net/kbZhU/1/
演示：http : //jsfiddle.net/kbZhU/1/
The faster option is to use indexOfand substringmethods:
$(function(){
var alphabet = "ABCDEFGHIJKLMNOPQRSTUVEXYZ";
var replaced = alphabet.substring(alphabet.indexOf("M") + 1);
$('body').text(replaced);
});
DEMO:http://jsfiddle.net/kbZhU/2/?
演示：http : //jsfiddle.net/kbZhU/2/？
回答by morex87
回答by Will
FYI if you are trying to do this with more than one letter, you have to change it a bit.
仅供参考，如果您尝试使用多个字母来执行此操作，则必须对其进行一些更改。
Using @VisioN solution I was trying to replace anything in a URL up to a certain point.
使用@VisioN 解决方案，我试图在某个特定点替换 URL 中的任何内容。
So to get everything after 'google.com' in https://www.google.com/analytics, I had to do
所以为了在 'google.com' 之后获得所有内容https://www.google.com/analytics，我必须这样做
const url = 'https://www.google.com/analytics'
const lookingFor = 'google.com'
const replaced = url.substring(url.indexOf(lookingFor) + lookingFor.length)
replacedwill then return /analytics
replaced然后会回来 /analytics
