如何在 PHP 中验证电子邮件？
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How to validate an Email in PHP?
提问by learner
How can I validate the input value is a valid email address using php5. Now I am using this code
如何使用php5验证输入值是有效的电子邮件地址。现在我正在使用此代码
function isValidEmail($email){
$pattern = "^[_a-z0-9-]+(\.[_a-z0-9-]+)*@[a-z0-9-]+(\.[a-z0-9-]+)*(\.[a-z]{2,3})$";
if (eregi($pattern, $email)){
return true;
}
else {
return false;
}
}
but it shows deprecated error. How can I fix this issue. Please help me.
但它显示已弃用的错误。我该如何解决这个问题。请帮我。
回答by kapa
You can use the filter_var()function, which gives you a lot of handy validation and sanitization options.
您可以使用该filter_var()功能，它为您提供了许多方便的验证和清理选项。
filter_var($email, FILTER_VALIDATE_EMAIL)
Available in PHP >= 5.2.0
适用于PHP >= 5.2.0
If you don't want to change your code that relied on your function, just do:
如果您不想更改依赖于您的函数的代码，请执行以下操作：
function isValidEmail($email){
return filter_var($email, FILTER_VALIDATE_EMAIL) !== false;
}
Note: For other uses (where you need Regex), the deprecated eregfunction family (POSIX Regex Functions) should be replaced by the pregfamily (PCRE Regex Functions). There are a small amount of differences, reading the Manual should suffice.
注意：对于其他用途（需要 Regex 的地方），不推荐使用的ereg函数系列 (POSIX Regex Functions) 应替换为preg系列 ( PCRE Regex Functions)。有少量差异，阅读手册就足够了。
Update 1: As pointed out by @binaryLV:
更新 1：正如@binaryLV所指出的：
PHP 5.3.3 and 5.2.14 had a bugrelated to FILTER_VALIDATE_EMAIL, which resulted in segfault when validating large values. Simple and safe workaround for this is using
strlen()beforefilter_var(). I'm not sure about 5.3.4 final, but it is written that some 5.3.4-snapshot versions also were affected.
PHP 5.3.3 和 5.2.14 有一个与 FILTER_VALIDATE_EMAIL 相关的错误，这会导致在验证大值时出现段错误。简单而安全的解决方法是使用
strlen()beforefilter_var()。我不确定 5.3.4 最终版的情况，但据说某些 5.3.4 快照版本也受到了影响。
This bug has already been fixed.
这个bug已经修复了。
Update 2: This method will of course validate bazmega@kapaas a valid email address, because in fact it is a valid email address. But most of the time on the Internet, you also want the email address to have a TLD: [email protected]. As suggested in this blog post(link posted by @Istiaque Ahmed), you can augment filter_var()with a regex that will check for the existence of a dot in the domain part (will not check for a validTLD though):
更新 2：此方法当然会验证bazmega@kapa为有效的电子邮件地址，因为实际上它是一个有效的电子邮件地址。但大多数时候在 Internet 上，您还希望电子邮件地址具有 TLD：[email protected]. 正如这篇博文（@Istiaque Ahmed发布的链接）中所建议的那样，您可以filter_var()使用一个正则表达式进行扩充，该正则表达式将检查域部分中是否存在点（但不会检查有效的TLD）：
function isValidEmail($email) {
return filter_var($email, FILTER_VALIDATE_EMAIL)
&& preg_match('/@.+\./', $email);
}
As @Eliseo Ocampospointed out, this problem only exists before PHP 5.3, in that version they changed the regexand now it does this check, so you do not have to.
正如@Eliseo Ocampos 所指出的，这个问题只存在于 PHP 5.3 之前，在那个版本中他们改变了正则表达式，现在它会进行这个检查，所以你不必这样做。
回答by Sean Kelleher
See the notes at http://www.php.net/manual/en/function.ereg.php:
请参阅http://www.php.net/manual/en/function.ereg.php 上的注释：
Note:As of PHP 5.3.0, the regex extension is deprecated in favor of the PCRE extension. Calling this function will issue an E_DEPRECATED notice. See the list of differencesfor help on converting to PCRE.
Note:preg_match(), which uses a Perl-compatible regular expression syntax, is often a faster alternative to ereg().
Note:从 PHP 5.3.0 开始，regex 扩展已被弃用，取而代之的是PCRE 扩展。调用此函数将发出 E_DEPRECATED 通知。有关 转换为 PCRE 的帮助，请参阅差异列表。
Note:preg_match()使用与 Perl 兼容的正则表达式语法，通常是 ereg() 的更快替代方法。
回答by Ivijan Stefan Stipi?
This is old post but I will share one my solution because noone mention here one problem before.
这是旧帖子，但我会分享一个我的解决方案，因为之前没有人在这里提到过一个问题。
New email address can contain UTF-8 characters or special domain names like .live, .newsetc.
新的电子邮件地址可以包含UTF-8字符或特殊域名，如.live，.news等。
Also I find that some email address can be on Cyrilic and on all cases standard regex or filter_var()will fail.
此外，我发现某些电子邮件地址可以使用 Cyrilic，并且在所有情况下都可以使用标准正则表达式，否则filter_var()会失败。
That's why I made an solution for it:
这就是为什么我为它制定了解决方案：
function valid_email($email)
{
if(is_array($email) || is_numeric($email) || is_bool($email) || is_float($email) || is_file($email) || is_dir($email) || is_int($email))
return false;
else
{
$email=trim(strtolower($email));
if(filter_var($email, FILTER_VALIDATE_EMAIL)!==false) return $email;
else
{
$pattern = '/^(?!(?:(?:\x22?\x5C[\x00-\x7E]\x22?)|(?:\x22?[^\x5C\x22]\x22?)){255,})(?!(?:(?:\x22?\x5C[\x00-\x7E]\x22?)|(?:\x22?[^\x5C\x22]\x22?)){65,}@)(?:(?:[\x21\x23-\x27\x2A\x2B\x2D\x2F-\x39\x3D\x3F\x5E-\x7E]+)|(?:\x22(?:[\x01-\x08\x0B\x0C\x0E-\x1F\x21\x23-\x5B\x5D-\x7F]|(?:\x5C[\x00-\x7F]))*\x22))(?:\.(?:(?:[\x21\x23-\x27\x2A\x2B\x2D\x2F-\x39\x3D\x3F\x5E-\x7E]+)|(?:\x22(?:[\x01-\x08\x0B\x0C\x0E-\x1F\x21\x23-\x5B\x5D-\x7F]|(?:\x5C[\x00-\x7F]))*\x22)))*@(?:(?:(?!.*[^.]{64,})(?:(?:(?:xn--)?[a-z0-9]+(?:-+[a-z0-9]+)*\.){1,126}){1,}(?:(?:[a-z][a-z0-9]*)|(?:(?:xn--)[a-z0-9]+))(?:-+[a-z0-9]+)*)|(?:\[(?:(?:IPv6:(?:(?:[a-f0-9]{1,4}(?::[a-f0-9]{1,4}){7})|(?:(?!(?:.*[a-f0-9][:\]]){7,})(?:[a-f0-9]{1,4}(?::[a-f0-9]{1,4}){0,5})?::(?:[a-f0-9]{1,4}(?::[a-f0-9]{1,4}){0,5})?)))|(?:(?:IPv6:(?:(?:[a-f0-9]{1,4}(?::[a-f0-9]{1,4}){5}:)|(?:(?!(?:.*[a-f0-9]:){5,})(?:[a-f0-9]{1,4}(?::[a-f0-9]{1,4}){0,3})?::(?:[a-f0-9]{1,4}(?::[a-f0-9]{1,4}){0,3}:)?)))?(?:(?:25[0-5])|(?:2[0-4][0-9])|(?:1[0-9]{2})|(?:[1-9]?[0-9]))(?:\.(?:(?:25[0-5])|(?:2[0-4][0-9])|(?:1[0-9]{2})|(?:[1-9]?[0-9]))){3}))\]))$/iD';
return (preg_match($pattern, $email) === 1) ? $email : false;
}
}
}
This function work perfectly for all cases and email formats.
此功能适用于所有案例和电子邮件格式。
回答by unbreak
I always use this:
我总是用这个：
function validEmail($email){
// First, we check that there's one @ symbol, and that the lengths are right
if (!preg_match("/^[^@]{1,64}@[^@]{1,255}$/", $email)) {
// Email invalid because wrong number of characters in one section, or wrong number of @ symbols.
return false;
}
// Split it into sections to make life easier
$email_array = explode("@", $email);
$local_array = explode(".", $email_array[0]);
for ($i = 0; $i < sizeof($local_array); $i++) {
if (!preg_match("/^(([A-Za-z0-9!#$%&'*+\/=?^_`{|}~-][A-Za-z0-9!#$%&'*+\/=?^_`{|}~\.-]{0,63})|(\"[^(\|\")]{0,62}\"))$/", $local_array[$i])) {
return false;
}
}
if (!preg_match("/^\[?[0-9\.]+\]?$/", $email_array[1])) { // Check if domain is IP. If not, it should be valid domain name
$domain_array = explode(".", $email_array[1]);
if (sizeof($domain_array) < 2) {
return false; // Not enough parts to domain
}
for ($i = 0; $i < sizeof($domain_array); $i++) {
if (!preg_match("/^(([A-Za-z0-9][A-Za-z0-9-]{0,61}[A-Za-z0-9])|([A-Za-z0-9]+))$/", $domain_array[$i])) {
return false;
}
}
}
return true;
}
回答by Jabari
Stay away from regexand filter_var()solutions for validating email. See this answer: https://stackoverflow.com/a/42037557/953833
从远点regex和filter_var()用于验证电子邮件解决方案。看到这个答案：https: //stackoverflow.com/a/42037557/953833
回答by Roman
Use:
用：
- or "filter_var" from http://php.net/manual/en/function.filter-var.php
- 或来自http://php.net/manual/en/function.filter-var.php 的“filter_var”
var_dump(filter_var('[email protected]', FILTER_VALIDATE_EMAIL));
- or "EmailValidator" from https://github.com/egulias/EmailValidator
- 或来自https://github.com/egulias/EmailValidator 的“EmailValidator”
$validator = new EmailValidator();
$multipleValidations = new MultipleValidationWithAnd([
new RFCValidation(),
new DNSCheckValidation()
]);
$validator->isValid("[email protected]", $multipleValidations); //true
