如何在 Postgresql 中转义下划线

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时间:2020-10-21 02:19:24  来源:igfitidea点击:

How to escape underscores in Postgresql

postgresqlescapingwildcardpostgresql-9.3

提问by Joe M

When searching for underscores in Postgresql, literal use of the character _doesn't work. For example, if you wanted to search all your tables for any columns that ended in _by, for something like change log or activity information, e.g. updated_by, reviewed_by, etc., the following query almost works:

在 Postgresql 中搜索下划线时,字符的字面使用_不起作用。例如,如果你想搜索,在结束的列所有的表_by,这样的事情更改日志或活动信息,例如updated_byreviewed_by等等,下面的查询工作差不多:

SELECT table_name, column_name FROM information_schema.columns
WHERE column_name LIKE '%_by'

It basically ignores the underscore completely and returns as if you'd searched for LIKE '%by'. This may not be a problem in all cases, but it has the potential to be one. How to search for underscores?

它基本上完全忽略下划线并返回,就像您搜索LIKE '%by'. 这可能不是所有情况下的问题,但它有可能成为一个问题。如何搜索下划线?

回答by Joe M

You need to use a backslash to escape the underscore. Change the example query to the following:

您需要使用反斜杠来转义下划线。将示例查询更改为以下内容:

SELECT table_name, column_name FROM information_schema.columns
WHERE column_name LIKE '%\_by'

回答by Taylor D

Just ran into the same issue and the single backslash wasn't working as well. I found this documentation on the PostgreSQL community and it worked:

刚遇到同样的问题,单个反斜杠也不起作用。我在 PostgreSQL 社区上找到了这个文档并且它有效:

The correct way is to escape the underscore with a backslash. You actually have to write two backslashes in your query:

select * from foo where bar like '%\\_baz'

The first backslash quotes the second one for the query parser, so that what ends up inside the system is %\_baz, and then the LIKE function knows what to do with that.

正确的方法是用反斜杠转义下划线。您实际上必须在查询中写入两个反斜杠:

select * from foo where bar like '%\\_baz'

第一个反斜杠引用查询解析器的第二个反斜杠,因此系统内部最终是 %\_baz,然后 LIKE 函数知道如何处理它。

Therefore use something like this:

因此使用这样的东西:

SELECT table_name, column_name FROM information_schema.columns
WHERE column_name LIKE '%\_by'

Source Documentation: https://www.postgresql.org/message-id/10965.962991238%40sss.pgh.pa.us

源文档:https: //www.postgresql.org/message-id/10965.962991238%40sss.pgh.pa.us