Python 不可订阅
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Python unsubscriptable
提问by Theodor
What does unsubscriptablemean in the context of a TypeError as in:
unsubscriptable在 TypeError 的上下文中是什么意思，如下所示：
TypeError: 'int' object is unsubscriptable
EDIT: Short code example that results in this phenomena.
编辑：导致这种现象的短代码示例。
a=[[1,2],[5,3],5,[5,6],[2,2]]
for b in a:
print b[0]
> 1
> 5
> TypeError: 'int' object is unsubscriptable
采纳答案by kichik
It means you tried treating an integer as an array. For example:
这意味着您尝试将整数视为数组。例如：
a = 1337
b = [1,3,3,7]
print b[0] # prints 1
print a[0] # raises your exception
回答by camh
You are trying to lookup an array subscript of an int:
您正在尝试查找 int 的数组下标：
>>> 1[0]
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: 'int' object is unsubscriptable
That is, square brackets []are the subscript operator. If you try to apply the subscript operator to an object that does not support it (such as not implementing __getitem__()).
也就是说，方括号[]是下标运算符。如果您尝试将下标运算符应用于不支持它的对象（例如未实现__getitem__()）。
回答by Sean Reifschneider
The problem in your sample code is that the array "a" contains two different types: it has 4 2-element lists and one integer. You are then trying to sub-script every element in "a", including the integer element.
您的示例代码中的问题是数组“a”包含两种不同的类型：它有 4 个 2 元素列表和一个整数。然后，您尝试为“a”中的每个元素添加下标，包括整数元素。
In other words, your code is effectively doing:
换句话说，您的代码正在有效地执行以下操作：
print [1,2][0]
print [5,3][0]
print 5[0]
print [5,6][0]
print [2,2][0]
That middle line where it does "5[0]" is what is generating the error.
它执行“5[0]”的中间线是产生错误的原因。
