Ruby - 合并两个数组并删除重复的值
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Ruby - Merge two arrays and remove values that have duplicate
提问by user3204760
I have two arrays
我有两个数组
a = [1, 2, 3, 4, 5]
b = [2, 4, 6]
I would like to merge the two arrays, then remove the values that is the same with other array. The result should be:
我想合并两个数组，然后删除与其他数组相同的值。结果应该是：
c = [1, 3, 5, 6]
I've tried subtracting the two array and the result is [1, 3, 5]. I also want to get the values from second array which has not duplicate from the first array..
我试过将两个数组相减，结果是 [1, 3, 5]。我还想从第二个数组中获取与第一个数组不重复的值。
采纳答案by Rubyrider
You can do the following!
你可以做到以下几点！
# Merging
c = a + b
=> [1, 2, 3, 4, 5, 2, 4, 6]
# Removing the value of other array
# (a & b) is getting the common element from these two arrays
c - (a & b)
=> [1, 3, 5, 6]
Dmitri's comment is also same though I came up with my idea independently.
Dmitri 的评论也是一样的，虽然我是独立提出我的想法的。
回答by EJAg
Use Array#uniq.
使用Array#uniq.
a = [1, 3, 5, 6]
b = [2, 3, 4, 5]
c = (a + b).uniq
=> [1, 3, 5, 6, 2, 4]
回答by ironsand
How about this．
这个怎么样。
(a | b)
=> [1, 2, 3, 4, 5, 6]
(a & b)
=> [2, 4]
(a | b) - (a & b)
[1, 3, 5, 6]
回答by noraj
回答by V K Singh
Let's have two array
让我们有两个数组
p = [1, 2, 5, 4, 8, 9]
q = [5, 6, 4, 8, 5, 3]
(p+q).uniq or (p.concat(q)).uniq
=> [1, 2, 5, 4, 8, 9, 6, 3]
Also p|qcan do the job! Decide which one suits for you.
也p|q能胜任！决定哪一种适合你。
回答by Sig
How about Set.new([1,2,3]+[1,4,5])?
Which returns [1,2,3,4,5]
怎么样Set.new([1,2,3]+[1,4,5])？哪个返回[1,2,3,4,5]
