php 来自foreach的php随机顺序

php random order from a foreach

提问by fish man

I have some foreach, this could work well

我有一些 foreach，这可以很好地工作

foreach ($umm as $data) {
        echo '<img src="'.$data->picture.'" />';
        echo  $data->id;
}

Now I want shuffle the foreach. I tried:

现在我想洗牌 foreach。我试过：

foreach (shuffle($umm) as $data) {
        echo '<img src="'.$data->picture.'" />';
        echo  $data->id;
}

AND

和

foreach ($umm as $data) {
        $rand_pic[] = $data->picture;
        $rand_id[] = $data->id;
}
$ran = shuffle($rand_id);
foreach($ran as $new){
    echo '<img src="'.$new->picture.'" width="100" />';
    echo $new->id;
}

All these caused Warning: Invalid argument supplied for foreach()in second foreach. How to random order from a foreach?

这一切都是Warning: Invalid argument supplied for foreach()在第二次造成的foreach。如何从foreach中随机排序？

回答by Ry-

Take a look at the documentation for shuffle(). It takes a referenceto an array and shuffles it in place. So you need to use it on the array, then iterate:

看一看文档shuffle()。它需要对数组的引用并将其改组到位。所以你需要在数组上使用它，然后迭代：

shuffle($umm);

foreach ($umm as $data) {
        echo '<img src="'.$data->picture.'" />';
        echo  $data->id;
}

回答by HorusKol

shuffle()returns a boolean - you pass the array by reference

shuffle()返回一个布尔值 - 您通过引用传递数组

Try this:

尝试这个：

shuffle($umm);
foreach($umm as $new){
    echo '<img src="'.$new->picture.'" width="100" />';
    echo $new->id;
}

回答by Rafiqul Islam

Try This Shuffle:

试试这个洗牌：

<?php 
   shuffle($umm);
   foreach($umm as $key => $value): ?>
 <img src="<?php echo $value->picture; ?>" alt="<?php echo $value->title;?>" />
 <?php echo $value->id;?>   
<?php endforeach; ?>