Java 格式日期从“MMM dd, yyyy HH:mm:ss a”到“MM.dd”
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format date from "MMM dd, yyyy HH:mm:ss a" to "MM.dd
提问by Nishant
I want to format date from "MMM dd, yyyy HH:mm:ss a" to "MM.dd". I have following code
我想将日期从“MMM dd, yyyy HH:mm:ss a”格式化为“MM.dd”。我有以下代码
SimpleDateFormat ft = new SimpleDateFormat ("MMM dd, yyyy hh:mm:ss a");
t = ft.parse(date); //Date is Sep 16, 2015 10:34:23 AM and of type string.
ft.applyPattern("MM.dd");
but I am getting exception at t = ft.parse(date);
但我在 t = ft.parse(date);
Please help
请帮忙
采纳答案by CupawnTae
Three possible explanations:
三种可能的解释：
- your default locale is incompatible with the input date - e.g. it can't understand
Sepas a month name - there's something wrong with the input string, or
tis the wrong type (e.g.java.sql.Dateinstead ofjava.util.Date, or some other type altogether), or is not declared.
- 您的默认语言环境与输入日期不兼容 - 例如它不能理解
Sep为月份名称 - 输入字符串有问题，或者
t是错误的类型（例如java.sql.Date代替java.util.Date，或其他类型），或未声明。
You should include details of the exception in your question to figure out which it is, but here's a working example using basically your own code, with the addition of a specific Locale.
您应该在问题中包含异常的详细信息以找出它是哪个，但这里有一个工作示例，基本上使用您自己的代码，并添加了特定的Locale.
SimpleDateFormat ft = new SimpleDateFormat("MMM dd, yyyy hh:mm:ss a", Locale.US);
java.util.Date t=ft.parse("Sep 16, 2015 10:34:23 AM");
ft.applyPattern("MM.dd");
System.out.println(ft.format(t));
output:
输出：
09.16
回答by rafaelasguerra
SimpleDateFormat sdf = new SimpleDateFormat("MM.dd", Locale.US);
System.out.println("Formatted Date: " + sdf.format(date));
