java Selenium WebDriver 中的 sendKeys()
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sendKeys() in Selenium WebDriver
提问by cxyz
I am new to Selenium and I am trying to upload a file using WebDriver. Here I am trying to click browse button using dom element as follows:
我是 Selenium 的新手，我正在尝试使用 WebDriver 上传文件。在这里，我尝试使用 dom 元素单击浏览按钮，如下所示：
selenium.type("document.forms['UploadForm'].elements['browsebutton']",file.getAbsolutePath());
But since the approach did not work am trying to hit browse button using WebDriver element as below: How can i change my dom element to xpath or css selector as below?
但是由于该方法不起作用，我尝试使用 WebDriver 元素点击浏览按钮，如下所示： 如何将我的 dom 元素更改为 xpath 或 css 选择器，如下所示？
driver.findElement(By.cssSelector("input[type=\"file\"]")).click();
I cant write xpath as
我不能将 xpath 写为
selenium.click("xpath="//input[@name='uplaod' and @value='browsebutton']");
since i have multiple browse buttons with same name and value.. So i need to pick using dom element itself. How do i do it?
因为我有多个具有相同名称和值的浏览按钮..所以我需要选择使用 dom 元素本身。我该怎么做？
Thanks in advance for help.
预先感谢您的帮助。
Dominik i have tried using the below xpath since there is no name attribute:But not working
Dominik 我已经尝试使用下面的 xpath，因为没有 name 属性：但不工作
String upload="(//input[@name='bulkUnBlockUploadForm' and @value='requestFile'])[2]";
String button="(//input[@name='bulkUnBlockUploadForm' and @value='process'])[2]";
I tried using id as well:Not working
我也尝试使用 id：不工作
String upload="(//input[@id='content' and @value='requestFile'])[1]";
String button="(//input[@id='content' and @value='process'])[1]";
The issue is in my jsp,i have 2 browse buttons s with same id and same value,but different form.I have 2 submit buttons for each of browse buttons with same id and same value,but different forms.So when am using the above approaches its hitting both the submit buttons
问题出在我的 jsp 中，我有 2 个具有相同 id 和相同值但不同形式的浏览按钮。对于每个具有相同 id 和相同值但不同形式的浏览按钮，我有 2 个提交按钮。所以当我使用上面接近它同时点击提交按钮
回答by Ankit jain
This can upload a file, it is work for me.
这可以上传文件，这对我有用。
public static void main(String[] args)
{
WebDriver driver = new FirefoxDriver();
driver.get("http://www.freepdfconvert.com/");
driver.findElement(By.id("UploadedFile")).sendKeys("C:\Users\Reputa\Downloads\HP1.pdf");
try {
Thread.sleep(4000);
} catch (Exception e) {}
driver.findElement(By.name("pdfsubmit")).click();
}
回答by sameer joshi
hi when iam beginner i also find a same issue someone told me you cant handle windows controls so use third party application such autoit , iam using autoit.
嗨，当我是初学者时，我也发现了同样的问题，有人告诉我您无法处理 Windows 控件，因此请使用第三方应用程序，例如 autoit，我正在使用 autoit。
1. download autoit.
2. no need of any jars just add Runtime,getruntime().execute('path of exe');in your code
3.code of file upload is below
Local $hWnd=WinWait("[CLASS:#32770]","",10)
ControlFocus($hWnd,"","Edit1")
Sleep(2000)
ControlSetText($hWnd, "", "Edit1", "path of file to upload")
Sleep(2000)
ControlClick($hWnd, "","Button1");
4 run your java application still if you find query ask me.
4 如果您发现查询，请继续运行您的 Java 应用程序。
回答by dokaspar
If you have two buttons with equal attributes, then either rename them to be better accessible (for example by giving them a unique id) or try to change your XPath statement to something like this:
如果您有两个具有相同属性的按钮，那么要么将它们重命名以使其更易于访问（例如通过给它们一个唯一的 id）或尝试将您的 XPath 语句更改为如下所示：
String uploadButton1 = "(//input[@name='upload' and @value='browsebutton'])[1]";
String uploadButton2 = "(//input[@name='upload' and @value='browsebutton'])[2]";
driver.findElement(By.xpath(uploadButton1)).click();
driver.findElement(By.xpath(uploadButton2)).click();
