如何将整数（例如 19000101 ）转换为 java.util.Date？
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How can I convert an Integer (e.g 19000101 ) to java.util.Date?
提问by sbanerjee
Here's my code:
这是我的代码：
Integer value = 19000101 ;
How can I convert the above Integer represented in YYYYMMDDformat to YYYY-MM-DDformat in java.util.Date?
如何将上述YYYYMMDD以YYYY-MM-DD格式表示的整数转换为格式 java.util.Date？
采纳答案by Adi
First you have to parse your format into date object using formatter specified
首先，您必须使用指定的格式化程序将格式解析为日期对象
Integer value = 19000101;
SimpleDateFormat originalFormat = new SimpleDateFormat("yyyyMMdd");
Date date = originalFormat.parse(value.toString());
Remember that Date has no format. It just represents specific instance in time in milliseconds starting from 1970-01-01. But if you want to format that date to your expected format, you can use another formatter.
请记住，日期没有格式。它仅代表从 1970-01-01 开始的以毫秒为单位的特定时间实例。但是如果您想将该日期格式化为您期望的格式，您可以使用另一个格式化程序。
SimpleDateFormat newFormat = new SimpleDateFormat("yyyy-MM-dd");
String formatedDate = newFormat.format(date);
Now your formatedDateString should contain string that represent date in format yyyy-MM-dd
现在你的formatedDateString 应该包含以格式表示日期的字符串yyyy-MM-dd
回答by Rahul Tripathi
Try this:
尝试这个：
String myDate= new SimpleDateFormat("yyyy-MM-dd HH:mm:ss")
.format(new Date(19000101 * 1000L));
Assuming it is the time since 1/1/1970
假设它是自 1/1/1970 以来的时间
EDIT:-
编辑：-
If you want to convert from YYYYMMDD to YYYY-MM-DD format
如果要将 YYYYMMDD 格式转换为 YYYY-MM-DD 格式
Date dt = new SimpleDateFormat("yyyyMMdd", Locale.ENGLISH).parse(String.ValueOf(19000101));
回答by Alexis King
It seems to me that you don't really have a numberrepresenting your date, you have a string of three numbers: year, month, and day. You can extract those values with some simple arithmetic.
在我看来，您实际上并没有代表日期的数字，而是一串三个数字：年、月和日。您可以使用一些简单的算术提取这些值。
Integer value = 19000101;
int year = value / 10000;
int month = (value % 10000) / 100;
int day = value % 100;
Date date = new GregorianCalendar(year, month, day).getTime();
