java 如何用连续数字填充数组
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How do I fill an array with consecutive numbers
提问by Dan
I would like to fill an array using consecutive integers. I have created an array that contains as much indexes as the user enters:
我想使用连续整数填充数组。我创建了一个包含与用户输入一样多的索引的数组：
Scanner in = new Scanner(System.in);
int numOfValues = in.nextInt();
int [] array = new int[numOfValues];
How do i fill this array with consecutive numbers starting from 1? All help is appreciated!!!
我如何用从 1 开始的连续数字填充这个数组？感谢所有帮助！！！
回答by Sotirios Delimanolis
Since Java 8
从 Java 8 开始
// v end, exclusive
int[] array = IntStream.range(1, numOfValues + 1).toArray();
// ^ start, inclusive
The rangeis in increments of 1. The javadoc is here.
以 1range为增量。javadoc 在这里。
Or use rangeClosed
或使用 rangeClosed
// v end, inclusive
int[] array = IntStream.rangeClosed(1, numOfValues).toArray();
// ^ start, inclusive
回答by user253751
The simple way is:
简单的方法是：
int[] array = new int[NumOfValues];
for(int k = 0; k < array.length; k++)
array[k] = k + 1;
回答by dave823
for(int i=0; i<array.length; i++)
{
array[i] = i+1;
}
回答by brobee
One more thing. If I want to do the same with reverse:
还有一件事。如果我想对反向做同样的事情：
int[] array = new int[5];
for(int i = 5; i>0;i--) {
array[i-1]= i;
}
System.out.println(Arrays.toString(array));
}
I got the normal order again..
我又得到了正常的订单..
回答by Neverwork2123
You now have an empty array
你现在有一个空数组
So you need to iterate over each position (0 to size-1) placing the next number into the array.
因此，您需要遍历每个位置（0 到 size-1），将下一个数字放入数组中。
for(int x=0; x<NumOfValues; x++){ // this will iterate over each position
array[x] = x+1; // this will put each integer value into the array starting with 1
}
回答by Dan
Scanner in = new Scanner(System.in);
int numOfValues = in.nextInt();
int[] array = new int[numOfValues];
int add = 0;
for (int i = 0; i < array.length; i++) {
array[i] = 1 + add;
add++;
System.out.println(array[i]);
}
