bash 我们如何在 shell 脚本中将变量与字母分开？
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How do we separate variables from letters in shell scripting?
提问by John Hoffman
I tried printing "Dogs are the best." with this bash script.
我尝试打印“狗是最好的”。使用这个 bash 脚本。
#!/bin/bash
ANIMAL="Dog"
echo "$ANIMALs are the best."
exit
However, I got " are the best." printed out instead because the sin $ANIMALSis not separated from the variable. How do I separate it?
但是，我得到了“是最好的”。而是打印出来，因为sin$ANIMALS没有与变量分开。我如何分离它？
回答by kojiro
With braces: echo "${ANIMAL}s are the best."
带牙套： echo "${ANIMAL}s are the best."
With quotes: echo "$ANIMAL"'s are the best.'
带引号： echo "$ANIMAL"'s are the best.'
With printf: printf '%ss are the best.\n' "$ANIMAL"
使用 printf： printf '%ss are the best.\n' "$ANIMAL"
I wouldn't use the quotes one most of the time. I don't find it readable, but it's good to be aware of.
大多数时候我不会使用引号。我不觉得它可读，但知道它很好。
回答by phlogratos
Just surround the variable's name with curly braces.
只需用花括号将变量名括起来。
#!/bin/bash
ANIMAL="Dog"
echo "${ANIMAL}s are the best."
exit
回答by iamauser
#!/bin/bash
ANIMAL="Dog"
echo "{$ANIMAL}s are the best."
exit
The answer is no longer unique, but correct...
答案不再是唯一的，而是正确的……
回答by Imane Fateh
Move your variable outside the quotes in echo :
将变量移到 echo 的引号之外：
#!/bin/bash
ANIMAL="Dog"
echo $ANIMAL"s are the best."
exit
OR :
或者 ：
#!/bin/bash
ANIMAL="Dog"
echo "${ANIMAL}s are the best."
exit
Both worked for me
两者都对我来说有效
回答by user unknown
Useless quotation, useless exit. A finished script needs no help to exit but the exit will bite you when sourcing that script.
无用的引用，无用的退出。完成的脚本无需帮助即可退出，但在采购该脚本时退出会咬你。
ANIMAL=Dog
echo ${ANIMAL}s are the best.
