Java 从 android 的 Jersey Resftul webservice 传递和接收 JSON 对象
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Pass and receive JSON object from Jersey Resftul webservice from android
提问by Mudassir Shahzad
Scenario : Pass username and password in a json object to restful webservice and get a json object in return. Yeah, I know, Its simple but I can't get it work.
场景：将 json 对象中的用户名和密码传递给 restful webservice 并获得一个 json 对象作为回报。是的，我知道，它很简单，但我无法让它工作。
I have been trying to this from several days. So far, I have tried this:
从几天来我一直在尝试这个。到目前为止，我已经尝试过这个：
My restful webservice code
我的宁静网络服务代码
@POST
@Path("/testJson")
@Consumes(MediaType.APPLICATION_JSON)
@Produces(MediaType.APPLICATION_JSON)
public JSONObject testJson(JSONObject inputJsonObj) throws Exception {
JSONObject myjson = new JSONObject();
if(inputJsonObj != null){
System.out.println("=================================");
System.out.println("JSON object = " + inputJsonObj.toString());
System.out.println("=================================");
}
else{
System.out.println("JSON is NULL");
}
myjson.put("success", "1");
System.out.println(myjson.toString());
// return "string returned";
return myjson;
}
And inside my android acivity, the code is
在我的 android 活动中，代码是
// POST request to <service>/SaveVehicle
HttpPost request = new HttpPost(myURL);
request.setHeader("Accept", "application/json");
request.setHeader("Content-type", "application/json");
request.setHeader("user-agent", "Yoda");
try {
// Build JSON string
// JSONStringer vehicle = new JSONStringer().object()
// .key("getItInputTO").object().key("zipCode").value("90505")
// .key("financingOption").value("B").key("make")
// .value("Scion").key("baseAmountFinanced").value("12000")
// .key("modelYear").value("2010").key("trimCode")
// .value("6221").key("totalMSRP").value("15000")
// .key("aprRate").value("").endObject().endObject();
JSONObject myjson = new JSONObject();
myjson.put("1", "first");
myjson.put("2", "second");
StringEntity entity = new StringEntity(myjson.toString());
entity.setContentEncoding(new BasicHeader(HTTP.CONTENT_TYPE,"application/json; charset=utf-8"));
request.setEntity(entity);
// Send request to WCF service
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpContext localContext = new BasicHttpContext();
// HttpResponse response = httpClient.execute(request, localContext);
HttpResponse response = httpClient.execute(request);
resCode = response.getStatusLine().getStatusCode();
Toast.makeText(getApplicationContext(),
response.getStatusLine().getStatusCode() + "",
Toast.LENGTH_LONG).show();
if (resCode == 200) {
Toast.makeText(getApplicationContext(),
response.getStatusLine().getStatusCode() + "",
Toast.LENGTH_LONG).show();
HttpEntity entity2 = (HttpEntity) response.getEntity().getContent();
String text = getASCIIContentFromEntity(entity);
if(text!=null){
JSONObject obj = new JSONObject(text);
lblMsg.setText("Successful!");
}
// BufferedReader in = new BufferedReader(new
// InputStreamReader(response.getEntity().getContent()));
//
//
// String line = "";
// StringBuffer returnFromServer = new StringBuffer();
//
// while ((line = in.readLine()) != null) {
// returnFromServer.append(line);
// }
// // Toast what we got from server
// Toast.makeText(getApplicationContext(),
// returnFromServer.toString(), Toast.LENGTH_LONG).show();
//
// if (entity != null) {
// entity.consumeContent();
// }
}
} catch (Exception e) {
// TODO: handle exception
}
The commented sections show previous tries.
评论部分显示了以前的尝试。
Output that I get on server console
我在服务器控制台上得到的输出
=================================
JSON object = {}
=================================
{"success":"1"}
My server side receiver json object is not getting populated i don't know why.
我的服务器端接收器 json 对象没有被填充，我不知道为什么。
Note:
笔记：
- I have INTERNET and many other permissions in my android manifest.
- My webservice is up and running.
- I have all the required jars i.e. jersey, json etc
- I am using Tomcat 7 for restful webservice
- 我的 android 清单中有 INTERNET 和许多其他权限。
- 我的网络服务已启动并正在运行。
- 我有所有必需的罐子，即球衣、json 等
- 我正在使用 Tomcat 7 进行宁静的网络服务
I would highly appreciate any help. Thanks
我将不胜感激任何帮助。谢谢
回答by jean.deanny
I have the same problem as yours. I don't know why, but the temporary solution i am using is creating a class to handle those parameters.
我和你有同样的问题。我不知道为什么，但我使用的临时解决方案是创建一个类来处理这些参数。
That means using Hymanson to convert Json Object <=> "Your Class"
这意味着使用 Hymanson 转换 Json Object <=> "Your Class"
See this tutorial for more information: http://www.mkyong.com/webservices/jax-rs/json-example-with-jersey-Hymanson/
有关更多信息，请参阅本教程：http: //www.mkyong.com/webservices/jax-rs/json-example-with-jersey-Hymanson/
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And I just found this topic, it may be more useful than the upper solution: Jersey POST Method is receiving null values as parameters
而且我刚发现这个话题，可能比上层的解决方案更有用： Jersey POST Method is received null values as parameters
