ios 如何在 Swift 中将 JSON 数组解析为数组
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How to parse Array of JSON to array in Swift
提问by Ashh
I'm trying to parse JSON which is like below
我正在尝试解析如下所示的 JSON
[
{
"People": [
"Hyman",
"Jones",
"Rock",
"Taylor",
"Rob"
]
},
{
"People": [
"Rose",
"John"
]
},
{
"People": [
"Ted"
]
}
]
to an array which results in [ ["Hyman", "Jones", "Rock", "Taylor", "Rob"] , ["Rose", "John"], ["Ted"] ]
到一个数组，结果为 [ [["Hyman", "Jones", "Rock", "Taylor", "Rob"] , ["Rose", "John"], ["Ted"] ]
which is array of arrays.
这是数组的数组。
I tried with code below
我试过下面的代码
if let path = Bundle.main.path(forResource: "People", ofType: "json")
{
let peoplesArray = try! JSONSerialization.jsonObject(with: Data(contentsOf: URL(fileURLWithPath: path)), options: JSONSerialization.ReadingOptions()) as? [AnyObject]
for people in peoplesArray! {
print(people)
}
}
when I print "people" I get o/p as
当我打印“人”时，我得到 o/p 为
{
People = (
Hyman,
"Jones",
"Rock",
"Taylor",
"Rob"
);
}
{
People = (
"Rose",
"John"
);
}
.....
I'm confused how to parse when it has "People" repeated 3 times
当“People”重复 3 次时，我很困惑如何解析
Trying to display content in UITableView where my 1st cell has "Hyman" .."Rob" and Second cell has "Rose" , "John" and third cell as "Ted"
尝试在 UITableView 中显示内容，其中我的第一个单元格具有“Hyman”..“Rob”，第二个单元格具有“Rose”、“John”和第三个单元格为“Ted”
PLease help me to understand how to achieve this
请帮助我了解如何实现这一目标
采纳答案by Bista
var peoplesArray:[Any] = [
[
"People": [
"Hyman",
"Jones",
"Rock",
"Taylor",
"Rob"
]
],
[
"People": [
"Rose",
"John"
]
],
[
"People": [
"Ted"
]
]
]
var finalArray:[Any] = []
for peopleDict in peoplesArray {
if let dict = peopleDict as? [String: Any], let peopleArray = dict["People"] as? [String] {
finalArray.append(peopleArray)
}
}
print(finalArray)
output:
输出：
[["Hyman", "Jones", "Rock", "Taylor", "Rob"], ["Rose", "John"], ["Ted"]]
In your case, it will be:
在您的情况下，它将是：
if let path = Bundle.main.path(forResource: "People", ofType: "json") {
let peoplesArray = try! JSONSerialization.jsonObject(with: Data(contentsOf: URL(fileURLWithPath: path)), options: JSONSerialization.ReadingOptions()) as? [Any]
var finalArray:[Any] = []
for peopleDict in peoplesArray {
if let dict = peopleDict as? [String: Any], let peopleArray = dict["People"] as? [String] {
finalArray.append(peopleArray)
}
}
print(finalArray)
}
回答by mokagio
You can do this in an elegant and type safe way leveraging Swift 4 Decodable
您可以利用 Swift 4 以优雅且类型安全的方式执行此操作 Decodable
First define a type for your people array.
首先为您的 people 数组定义一个类型。
struct People {
let names: [String]
}
Then make it Decodable, so that it can be initialised with a JSON.
然后 make it Decodable，以便可以使用 JSON 对其进行初始化。
extension People: Decodable {
private enum Key: String, CodingKey {
case names = "People"
}
init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: Key.self)
self.names = try container.decode([String].self, forKey: .names)
}
}
Now you can easily decode your JSON input
现在您可以轻松解码您的 JSON 输入
guard
let url = Bundle.main.url(forResource: "People", withExtension: "json"),
let data = try? Data(contentsOf: url)
else { /* Insert error handling here */ }
do {
let people = try JSONDecoder().decode([People].self, from: data)
} catch {
// I find it handy to keep track of why the decoding has failed. E.g.:
print(error)
// Insert error handling here
}
Finally to get get your linear array of names you can do
最后得到你可以做的名字的线性数组
let names = people.flatMap { static func photosFromJSONObject(data: Data) -> photosResult {
do {
let jsonObject : Any =
try JSONSerialization.jsonObject(with: data, options: [])
print(jsonObject)
guard let
jsonDictionary = jsonObject as? [NSObject : Any] as NSDictionary?,
let trackObject = jsonDictionary["track"] as? [String : Any],
let album = trackObject["album"] as? [String : Any],
let photosArray = album["image"] as? [[String : Any]]
else { return .failure(lastFMError.invalidJSONData) }
}
.names }
// => ["Hyman", "Jones", "Rock", "Taylor", "Rob", "Rose", "John", "Ted"]
回答by anckydocky
I couldn't pasted it in a comment, it is too long or something
我无法将其粘贴到评论中，它太长或什么的
{
artist: {
name: Cher,
track: {
title: WhateverTitle,
album: {
title: AlbumWhatever,
image: {
small: "image.px",
medium: "image.2px",
large: "image.3px"}
....
And the json was something like:
json 是这样的：
var arrayOfData : [String] = []
dispatch_async(dispatch_get_main_queue(),{
for data in json as! [Dictionary<String,AnyObject>]
{
let data1 = data["People"]
arrayOfData.append(data1!)
}
})
回答by Gabriel M.
let assume that the json is the encoded data
假设 json 是编码数据
let peoplesArray = try! JSONSerialization.jsonObject(with: Data(contentsOf: URL(fileURLWithPath: path)), options: []) as? [AnyObject]
guard let peoplesObject = peoplesArray["people"] as? [[String:Any]] else { return }
for people in peoplesObject {
print("\(people)")
}
You can now use the arrayOfData. :D
您现在可以使用 arrayOfData。:D
回答by anckydocky
what you have here is first an array of 3 objects. each object is a dictionary where the key is people and the value is an array of strings. when you're trying to do jsonserialization, you have to cast it down to the expected result. So you have first an array of objects, then you have a dictionary with String: Any, then you obtain an array of String
你在这里首先是一个包含 3 个对象的数组。每个对象都是一个字典，其中键是人，值是一个字符串数组。当您尝试进行 jsonserialization 时，您必须将其转换为预期的结果。所以你首先有一个对象数组，然后你有一个带有字符串的字典：Any，然后你获得一个字符串数组
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