java 将字符串转换为 JNA 的指针
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Converting String to Pointer for JNA
提问by Kevin K
I'm trying to use JNA to query the effective permissions for a file in Windows. Eventually, I plan on using the GetEffectiveRightsFromAcl function, but to do so, I need to provide a pointer to a populated TRUSTEE structure. The JNA Platform (platform.jar) doesn't appear define this struct, so I'm trying to define it myself instead. Here's what I have so far:
我正在尝试使用 JNA 来查询 Windows 中文件的有效权限。最后,我计划使用GetEffectiveRightsFromAcl 函数,但为此,我需要提供一个指向填充的TRUSTEE 结构的指针。JNA 平台(platform.jar)似乎没有定义这个结构,所以我试图自己定义它。这是我到目前为止所拥有的:
public static class TRUSTEE extends Structure {
public TRUSTEE() {
super();
}
public TRUSTEE(Pointer p) {
super(p);
read();
}
public Pointer pMultipleTrustee;
public int MultipleTrusteeOperation;
public int TrusteeForm;
public int TrusteeType;
public Pointer ptstrName;
}
I'm trying to populate the structure like this:
我正在尝试填充这样的结构:
private TRUSTEE createTrusteeForCurrentUser() {
TRUSTEE result = new TRUSTEE();
result.TrusteeForm = TRUSTEE_FORM.TRUSTEE_IS_NAME;
result.TrusteeType = TRUSTEE_TYPE.TRUSTEE_IS_USER;
String strName = "CURRENT_USER";
// How can I set result.ptstrName using strName?
}
This Google Groups threadrecommends using String
fields in structures when a char *
is called for. However, I don't think this is appropriate in my situation, considering the ptstrName
field is allowed to point to different types of things, depending on the value of TrusteeForm
. So, I think I somehow need to convert from String
to Pointer
instead. I found the NativeStringclass in JNA, which would work, except it's a package-private class.
此 Google Groups 线程建议String
在char *
调用a 时使用结构中的字段。但是,我认为这不适合我的情况,考虑到ptstrName
允许字段指向不同类型的事物,具体取决于TrusteeForm
. 所以,我想我需要以某种方式从 转换String
为Pointer
。我在 JNA 中找到了NativeString类,它可以工作,但它是一个包私有类。
What's the recommended way to convert a Java String
to a native format and obtain a Pointer
to it? Am I even using the right data type for the TRUSTEE
struct? I'm somewhat new to JNA, so please excuse me if I'm missing something obvious.
将 Java 转换String
为本机格式并获得Pointer
它的推荐方法是什么?我什至为TRUSTEE
结构使用了正确的数据类型吗?我对 JNA 有点陌生,所以如果我遗漏了一些明显的东西,请原谅。
Update
更新
I found a solution to my problem, but if anyone has a better solution I'd still like to hear it.
我找到了解决我的问题的方法,但如果有人有更好的解决方案,我仍然希望听到它。
采纳答案by Kevin K
I solved the problem by copying the source code for package-private NativeString
class and creating a public copy in my project. I had to make one minor alteration due to the use of a package-private method in the constructor.
我通过复制包私有NativeString
类的源代码并在我的项目中创建一个公共副本来解决这个问题。由于在构造函数中使用了包私有方法,我不得不做一个小改动。
Update:As @fragorl notes in the comments, the implementation of NativeString shown below is by now quite out-of-date.
更新:正如@fragorl 在评论中指出的那样,下面显示的 NativeString 的实现现在已经过时了。
Usage:
用法:
private static TRUSTEE createTrusteeForCurrentUser() {
TRUSTEE result = new TRUSTEE();
result.TrusteeForm = TRUSTEE_FORM.TRUSTEE_IS_NAME;
result.TrusteeType = TRUSTEE_TYPE.TRUSTEE_IS_USER;
result.ptstrName = new NativeString("CURRENT_USER",true).getPointer();
result.write();
return result;
}
NativeString.java:
NativeString.java:
/** Provides a temporary allocation of an immutable C string
* (<code>const char*</code> or <code>const wchar_t*</code>) for use when
* converting a Java String into a native memory function argument.
*
* @author Todd Fast, [email protected]
* @author [email protected]
*/
public class NativeString implements CharSequence, Comparable {
private Pointer pointer;
private boolean wide;
/** Create a native string (NUL-terminated array of <code>char</code>).<p>
* If the system property <code>jna.encoding</code> is set, its value will
* be used to encode the native string. If not set or if the encoding
* is unavailable, the default platform encoding will be used.
*/
public NativeString(String string) {
this(string, false);
}
/** Create a native string as a NUL-terminated array of <code>wchar_t</code>
* (if <code>wide</code> is true) or <code>char</code>.<p>
* If the system property <code>jna.encoding</code> is set, its value will
* be used to encode the native <code>char</code>string.
* If not set or if the encoding is unavailable, the default platform
* encoding will be used.
*
* @param string value to write to native memory
* @param wide whether to store the String as <code>wchar_t</code>
*/
public NativeString(String string, boolean wide) {
if (string == null) {
throw new NullPointerException("String must not be null");
}
// Allocate the memory to hold the string. Note, we have to
// make this 1 element longer in order to accommodate the terminating
// NUL (which is generated in Pointer.setString()).
this.wide = wide;
if (wide) {
int len = (string.length() + 1 ) * Native.WCHAR_SIZE;
pointer = new Memory(len);
pointer.setString(0, string, true);
}
else {
byte[] data = Native.toByteArray(string);
pointer = new Memory(data.length + 1);
pointer.write(0, data, 0, data.length);
pointer.setByte(data.length, (byte)0);
}
}
public int hashCode() {
return toString().hashCode();
}
public boolean equals(Object other) {
if (other instanceof CharSequence) {
return compareTo(other) == 0;
}
return false;
}
public String toString() {
String s = wide ? "const wchar_t*" : "const char*";
s += "(" + pointer.getString(0, wide) + ")";
return s;
}
public Pointer getPointer() {
return pointer;
}
public char charAt(int index) {
return toString().charAt(index);
}
public int length() {
return toString().length();
}
public CharSequence subSequence(int start, int end) {
return CharBuffer.wrap(toString()).subSequence(start, end);
}
public int compareTo(Object other) {
if (other == null)
return 1;
return toString().compareTo(other.toString());
}
}
回答by technomage
Assuming you want char *
on the native side (you may need more memory allocated if the string contains non-ascii characters),
假设您想要char *
在本机端(如果字符串包含非 ascii 字符,您可能需要分配更多内存),
String myString = "CURRENT_USER";
Pointer m = new Memory(myString.length() + 1); // WARNING: assumes ascii-only string
m.setString(0, myString);
You can then use m
wherever you need to reference the "native" string.
然后,您可以m
在需要引用“本机”字符串的任何地方使用。
For wide strings (wchar_t *
),
对于宽字符串 ( wchar_t *
),
String myString = "CURRENT_USER";
Pointer m = new Memory(Native.WCHAR_SIZE * (myString.length() + 1));
m.setWideString(0, myString);
回答by UVM
try using Pointer class in http://jna.java.net/javadoc/com/sun/jna/Pointer.html.
尝试在http://jna.java.net/javadoc/com/sun/jna/Pointer.html 中使用 Pointer 类。