如何在 Java 中获取 URL 的 HTTP 响应代码？
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How to get HTTP response code for a URL in Java?
提问by Ajit
Please tell me the steps or code to get the response code of a particlular URL.
请告诉我获取特定 URL 响应代码的步骤或代码。
回答by Rob Hruska
URL url = new URL("http://example.com");
HttpURLConnection connection = (HttpURLConnection)url.openConnection();
connection.setRequestMethod("GET");
connection.connect();
int code = connection.getResponseCode();
This is by no means a robust example; you'll need to handle IOExceptions and whatnot. But it should get you started.
这绝不是一个可靠的例子；你需要处理IOExceptions 等等。但它应该让你开始。
If you need something with more capability, check out HttpClient.
如果您需要具有更多功能的东西，请查看HttpClient。
回答by kwo
URL url = new URL("http://www.google.com/humans.txt");
HttpURLConnection http = (HttpURLConnection)url.openConnection();
int statusCode = http.getResponseCode();
回答by Ashish Sharda
You could try the following:
您可以尝试以下操作：
class ResponseCodeCheck
{
public static void main (String args[]) throws Exception
{
URL url = new URL("http://google.com");
HttpURLConnection connection = (HttpURLConnection)url.openConnection();
connection.setRequestMethod("GET");
connection.connect();
int code = connection.getResponseCode();
System.out.println("Response code of the object is "+code);
if (code==200)
{
System.out.println("OK");
}
}
}
回答by Raja Singh
import java.io.IOException;
import java.net.URL;
import java.net.HttpURLConnection;
public class API{
public static void main(String args[]) throws IOException
{
URL url = new URL("http://www.google.com");
HttpURLConnection http = (HttpURLConnection)url.openConnection();
int statusCode = http.getResponseCode();
System.out.println(statusCode);
}
}
回答by neoeahit
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setDoOutput(true);
connection.setDoInput(true);
connection.setRequestMethod("POST");
. . . . . . .
. . . . . . .
System.out.println("Value" + connection.getResponseCode());
System.out.println(connection.getResponseMessage());
System.out.println("content"+connection.getContent());
回答by Jeverick
This is what worked for me:
这对我有用：
import java.io.IOException;
import java.net.HttpURLConnection;
import java.net.URL;
public class UrlHelpers {
public static int getHTTPResponseStatusCode(String u) throws IOException {
URL url = new URL(u);
HttpURLConnection http = (HttpURLConnection)url.openConnection();
return http.getResponseCode();
}
}
Hope this helps someone :)
希望这对某人有所帮助:)
回答by Subhasish Sahu
This has worked for me :
这对我有用：
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.HttpResponse;
import java.io.BufferedReader;
import java.io.InputStreamReader;
public static void main(String[] args) throws Exception {
HttpClient client = new DefaultHttpClient();
//args[0] ="http://hostname:port/xyz/zbc";
HttpGet request1 = new HttpGet(args[0]);
HttpResponse response1 = client.execute(request1);
int code = response1.getStatusLine().getStatusCode();
try(BufferedReader br = new BufferedReader(new InputStreamReader((response1.getEntity().getContent())));){
// Read in all of the post results into a String.
String output = "";
Boolean keepGoing = true;
while (keepGoing) {
String currentLine = br.readLine();
if (currentLine == null) {
keepGoing = false;
} else {
output += currentLine;
}
}
System.out.println("Response-->"+output);
}
catch(Exception e){
System.out.println("Exception"+e);
}
}
回答by captainchhala
you can use java http/https url connection to get the response code from the website and other information as well here is a sample code.
您可以使用 java http/https url 连接从网站和其他信息获取响应代码，这里是一个示例代码。
try {
url = new URL("https://www.google.com"); // create url object for the given string
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
if(https_url.startsWith("https")){
connection = (HttpsURLConnection) url.openConnection();
}
((HttpURLConnection) connection).setRequestMethod("HEAD");
connection.setConnectTimeout(50000); //set the timeout
connection.connect(); //connect
String responseMessage = connection.getResponseMessage(); //here you get the response message
responseCode = connection.getResponseCode(); //this is http response code
System.out.println(obj.getUrl()+" is up. Response Code : " + responseMessage);
connection.disconnect();`
}catch(Exception e){
e.printStackTrace();
}
回答by user8024555
Efficient way to get data(With uneven payload) by scanner.
通过扫描仪获取数据（负载不均匀）的有效方法。
public static String getResponseFromHttpUrl(URL url) throws IOException {
HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();
try {
InputStream in = urlConnection.getInputStream();
Scanner scanner = new Scanner(in);
scanner.useDelimiter("\A"); // Put entire content to next token string, Converts utf8 to 16, Handles buffering for different width packets
boolean hasInput = scanner.hasNext();
if (hasInput) {
return scanner.next();
} else {
return null;
}
} finally {
urlConnection.disconnect();
}
}
回答by lokesh sharma
Try this piece of code which is checking the 400 error messages
试试这段代码，它正在检查 400 错误消息
huc = (HttpURLConnection)(new URL(url).openConnection());
huc.setRequestMethod("HEAD");
huc.connect();
respCode = huc.getResponseCode();
if(respCode >= 400) {
System.out.println(url+" is a broken link");
} else {
System.out.println(url+" is a valid link");
}
