java JAX-RS 接受图像作为输入
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JAX-RS Accept Images as input
提问by Brams
For quite some time now, I've been developing JAX-RS web services for my development needs. All the methods that I've written so far accept java Strings or primitive types as input.
一段时间以来，我一直在开发 JAX-RS Web 服务以满足我的开发需求。到目前为止，我编写的所有方法都接受 java 字符串或原始类型作为输入。
An example of such a method:
这种方法的一个例子：
@POST
@Path("MyMethod")
@Produces(MediaType.APPLICATION_JSON)
public String MyMethod(@FormParam("username")String username, @FormParam("password")String passowrd)
What I'm trying to do now is accept images as input. I read a lot of articles regarding this. Some suggested accepting the base64 encoding as input and others suggested accepting an actual InputSteam.
我现在要做的是接受图像作为输入。我阅读了很多关于这方面的文章。有些人建议接受 base64 编码作为输入，而其他人则建议接受实际的 InputSteam。
However, i'm yet to see a full blown example on how to accept an InputStream. I read about the @consumer annotation and @Provider but i still can't wrap my head around it. Is there an article, documentation or an example that somehow guides me toward this? i.e. A step by step process on how to implement rather than displaying theory.
但是，我还没有看到有关如何接受 InputStream 的完整示例。我阅读了@consumer 注释和@Provider，但我仍然无法理解它。是否有文章、文档或示例以某种方式指导我进行此操作？即关于如何实施而不是展示理论的逐步过程。
I know that the base64 encoding works but out of curiosity i would like to know how the other approach works as well...Thanks in advance.
我知道 base64 编码有效，但出于好奇，我想知道其他方法也是如何工作的......提前致谢。
采纳答案by yegor256
This should work:
这应该有效：
import org.apache.commons.io.IOUtils;
@POST
@Path("MyMethod")
@Consumes("*/*") // to accept all input types
public String MyMethod(InputStream stream) {
byte[] image = IOUtils.toByteArray(stream);
return "done";
}
回答by Torsten R?mer
Probably not the preferred but a simple way to combine InputStreamwith one or more path parameters:
可能不是首选，而是一种InputStream与一个或多个路径参数结合的简单方法：
@POST
@Path("page/{page}")
@Consumes(MediaType.APPLICATION_OCTET_STREAM)
@Produces("image/jpeg")
public StreamingOutput generatePage(final InputStream inputStream, @Context UriInfo uriInfo) {
final int page = Integer.parseInt(uriInfo.getPathParameters().getFirst("page"));
return (outputStream) -> {
service.generatePage(page, inputStream, outputStream);
};
}
