string 如何使用批处理查看字符串是否包含子字符串
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How to see if a string contains a substring using batch
提问by FyreeW
Currently trying to see if a string, in this case the current line of a text file, contains a substring #. I am new to batch, so I am not sure exactly how I would do something like this. Here is the code
set substring = #
当前正在尝试查看字符串（在本例中为文本文件的当前行）是否包含子字符串#。我是批处理的新手，所以我不确定我将如何做这样的事情。这是代码
set substring = #
for /f "delims=," %%a in (Text.txt) do (
set string = %%a
//check substring method
echo %string%
)
回答by Magoo
echo %%a|find "substring" >nul
if errorlevel 1 (echo notfound) else (echo found)
Batch is sensitive to spaces in a SETstatement. SET FLAG = Nsets a variable named "FLAGSpace" to a value of "SpaceN"
批处理对SET语句中的空格敏感。SET FLAG = N将名为“FLAG Space”的变量设置为“ SpaceN”的值
The syntax SET "var=value"(where value may be empty) is used to ensure that any stray trailing spaces are NOT included in the value assigned. set /acan safely be used "quoteless".
语法SET "var=value"（其中 value 可能为空）用于确保分配的值中不包含任何杂散的尾随空格。set /a可以安全地使用“无引号”。
回答by aschipfl
As an alternative to find, you can use string substitution, like this:
作为替代find，您可以使用字符串替换，如下所示：
@echo off
setlocal EnableDelayedExpansion
set "substring=#"
for /f "delims=," %%a in (Text.txt) do (
set "string=%%a"
if "!string:%substring%=!"=="!string!" (
rem string with substring removed equals the original string,
rem so it does not contain substring; therefore, output it:
echo(!string!
)
)
endlocal
This approach uses delayed environment variable expansion. Type setlocal /?in command prompt to find out how to enable it, and set /?to see how it works (read variables like !string!instead of %string%) and what it means. set /?also describes the string substitution syntax.
这种方法使用延迟环境变量扩展。键入setlocal /?命令提示符以了解如何启用它，并set /?查看它是如何工作的（读取变量，!string!而不是%string%）及其含义。set /?还描述了字符串替换语法。
