php 从访问者的 IP 获取访问者所在的国家/地区
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Getting visitors country from their IP
提问by Alex C.
I want to get visitors country via their IP... Right now I'm using this (http://api.hostip.info/country.php?ip=...... )
我想通过他们的 IP 获取访问者的国家...现在我正在使用这个（http://api.hostip.info/country.php?ip=......）
Here is my code:
这是我的代码：
<?php
if (isset($_SERVER['HTTP_CLIENT_IP']))
{
$real_ip_adress = $_SERVER['HTTP_CLIENT_IP'];
}
if (isset($_SERVER['HTTP_X_FORWARDED_FOR']))
{
$real_ip_adress = $_SERVER['HTTP_X_FORWARDED_FOR'];
}
else
{
$real_ip_adress = $_SERVER['REMOTE_ADDR'];
}
$cip = $real_ip_adress;
$iptolocation = 'http://api.hostip.info/country.php?ip=' . $cip;
$creatorlocation = file_get_contents($iptolocation);
?>
Well, it's working properly, but the thing is, this returns the country code like US or CA., and not the whole country name like United States or Canada.
嗯，它工作正常，但问题是，这会返回像美国或加拿大这样的国家/地区代码，而不是像美国或加拿大这样的整个国家/地区名称。
So, is there any good alternative to hostip.info offers this?
那么，hostip.info 有什么好的替代方案吗？
I know that I can just write some code that will eventually turn this two letters to whole country name, but I'm just too lazy to write a code that contains all countries...
我知道我可以编写一些代码，最终将这两个字母转换为整个国家/地区的名称，但我懒得编写包含所有国家/地区的代码......
P.S: For some reason I don't want to use any ready made CSV file or any code that will grab this information for me, something like ip2country ready made code and CSV.
PS：出于某种原因，我不想使用任何现成的 CSV 文件或任何可以为我获取此信息的代码，例如 ip2country 的现成代码和 CSV。
回答by Chandra Nakka
Try this simple PHP function.
试试这个简单的 PHP 函数。
<?php
function ip_info($ip = NULL, $purpose = "location", $deep_detect = TRUE) {
$output = NULL;
if (filter_var($ip, FILTER_VALIDATE_IP) === FALSE) {
$ip = $_SERVER["REMOTE_ADDR"];
if ($deep_detect) {
if (filter_var(@$_SERVER['HTTP_X_FORWARDED_FOR'], FILTER_VALIDATE_IP))
$ip = $_SERVER['HTTP_X_FORWARDED_FOR'];
if (filter_var(@$_SERVER['HTTP_CLIENT_IP'], FILTER_VALIDATE_IP))
$ip = $_SERVER['HTTP_CLIENT_IP'];
}
}
$purpose = str_replace(array("name", "\n", "\t", " ", "-", "_"), NULL, strtolower(trim($purpose)));
$support = array("country", "countrycode", "state", "region", "city", "location", "address");
$continents = array(
"AF" => "Africa",
"AN" => "Antarctica",
"AS" => "Asia",
"EU" => "Europe",
"OC" => "Australia (Oceania)",
"NA" => "North America",
"SA" => "South America"
);
if (filter_var($ip, FILTER_VALIDATE_IP) && in_array($purpose, $support)) {
$ipdat = @json_decode(file_get_contents("http://www.geoplugin.net/json.gp?ip=" . $ip));
if (@strlen(trim($ipdat->geoplugin_countryCode)) == 2) {
switch ($purpose) {
case "location":
$output = array(
"city" => @$ipdat->geoplugin_city,
"state" => @$ipdat->geoplugin_regionName,
"country" => @$ipdat->geoplugin_countryName,
"country_code" => @$ipdat->geoplugin_countryCode,
"continent" => @$continents[strtoupper($ipdat->geoplugin_continentCode)],
"continent_code" => @$ipdat->geoplugin_continentCode
);
break;
case "address":
$address = array($ipdat->geoplugin_countryName);
if (@strlen($ipdat->geoplugin_regionName) >= 1)
$address[] = $ipdat->geoplugin_regionName;
if (@strlen($ipdat->geoplugin_city) >= 1)
$address[] = $ipdat->geoplugin_city;
$output = implode(", ", array_reverse($address));
break;
case "city":
$output = @$ipdat->geoplugin_city;
break;
case "state":
$output = @$ipdat->geoplugin_regionName;
break;
case "region":
$output = @$ipdat->geoplugin_regionName;
break;
case "country":
$output = @$ipdat->geoplugin_countryName;
break;
case "countrycode":
$output = @$ipdat->geoplugin_countryCode;
break;
}
}
}
return $output;
}
?>
How to use:
如何使用：
Example1: Get visitor IP address details
示例 1：获取访问者 IP 地址详细信息
<?php
echo ip_info("Visitor", "Country"); // India
echo ip_info("Visitor", "Country Code"); // IN
echo ip_info("Visitor", "State"); // Andhra Pradesh
echo ip_info("Visitor", "City"); // Proddatur
echo ip_info("Visitor", "Address"); // Proddatur, Andhra Pradesh, India
print_r(ip_info("Visitor", "Location")); // Array ( [city] => Proddatur [state] => Andhra Pradesh [country] => India [country_code] => IN [continent] => Asia [continent_code] => AS )
?>
Example 2: Get details of any IP address. [Support IPV4 & IPV6]
示例 2：获取任何 IP 地址的详细信息。[支持IPV4 & IPV6]
<?php
echo ip_info("173.252.110.27", "Country"); // United States
echo ip_info("173.252.110.27", "Country Code"); // US
echo ip_info("173.252.110.27", "State"); // California
echo ip_info("173.252.110.27", "City"); // Menlo Park
echo ip_info("173.252.110.27", "Address"); // Menlo Park, California, United States
print_r(ip_info("173.252.110.27", "Location")); // Array ( [city] => Menlo Park [state] => California [country] => United States [country_code] => US [continent] => North America [continent_code] => NA )
?>
回答by Baba
You can use a simple API from http://www.geoplugin.net/
您可以使用来自http://www.geoplugin.net/的简单 API
$xml = simplexml_load_file("http://www.geoplugin.net/xml.gp?ip=".getRealIpAddr());
echo $xml->geoplugin_countryName ;
echo "<pre>";
foreach ($xml as $key => $value)
{
echo $key , "= " , $value , " \n" ;
}
echo "</pre>";
Function Used
使用的功能
function getRealIpAddr()
{
if (!empty($_SERVER['HTTP_CLIENT_IP'])) //check ip from share internet
{
$ip=$_SERVER['HTTP_CLIENT_IP'];
}
elseif (!empty($_SERVER['HTTP_X_FORWARDED_FOR'])) //to check ip is pass from proxy
{
$ip=$_SERVER['HTTP_X_FORWARDED_FOR'];
}
else
{
$ip=$_SERVER['REMOTE_ADDR'];
}
return $ip;
}
Output
输出
United States
geoplugin_city= San Antonio
geoplugin_region= TX
geoplugin_areaCode= 210
geoplugin_dmaCode= 641
geoplugin_countryCode= US
geoplugin_countryName= United States
geoplugin_continentCode= NA
geoplugin_latitude= 29.488899230957
geoplugin_longitude= -98.398696899414
geoplugin_regionCode= TX
geoplugin_regionName= Texas
geoplugin_currencyCode= USD
geoplugin_currencySymbol= $
geoplugin_currencyConverter= 1
It makes you have so many options you can play around with
它让你有很多可以玩的选择
Thanks
谢谢
:)
:)
回答by Kai Noack
I tried Chandra's answer but my server configuration does not allow file_get_contents()
我尝试了 Chandra 的回答，但我的服务器配置不允许file_get_contents()
PHP Warning: file_get_contents() URL file-access is disabled in the server configuration
PHP Warning: file_get_contents() URL file-access is disabled in the server configuration
I modified Chandra's code so that it also works for servers like that using cURL:
我修改了 Chandra 的代码，使其也适用于使用 cURL 的服务器：
function ip_visitor_country()
{
$client = @$_SERVER['HTTP_CLIENT_IP'];
$forward = @$_SERVER['HTTP_X_FORWARDED_FOR'];
$remote = $_SERVER['REMOTE_ADDR'];
$country = "Unknown";
if(filter_var($client, FILTER_VALIDATE_IP))
{
$ip = $client;
}
elseif(filter_var($forward, FILTER_VALIDATE_IP))
{
$ip = $forward;
}
else
{
$ip = $remote;
}
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, "http://www.geoplugin.net/json.gp?ip=".$ip);
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, TRUE);
$ip_data_in = curl_exec($ch); // string
curl_close($ch);
$ip_data = json_decode($ip_data_in,true);
$ip_data = str_replace('"', '"', $ip_data); // for PHP 5.2 see stackoverflow.com/questions/3110487/
if($ip_data && $ip_data['geoplugin_countryName'] != null) {
$country = $ip_data['geoplugin_countryName'];
}
return 'IP: '.$ip.' # Country: '.$country;
}
echo ip_visitor_country(); // output Coutry name
?>
Hope that helps ;-)
希望有帮助;-)
回答by Marcus
Actually, you can call http://api.hostip.info/?ip=123.125.114.144to get the information, which is presented in XML.
实际上，您可以调用http://api.hostip.info/?ip=123.125.114.144来获取信息，该信息以 XML 形式呈现。
回答by Joyce Babu
Use MaxMind GeoIP (or GeoIPLite if you are not ready to pay).
使用 MaxMind GeoIP（如果您还没有准备好付款，则使用 GeoIPLite）。
$gi = geoip_open('GeoIP.dat', GEOIP_MEMORY_CACHE);
$country = geoip_country_code_by_addr($gi, $_SERVER['REMOTE_ADDR']);
geoip_close($gi);
回答by GBD
Use following services
使用以下服务
1) http://api.hostip.info/get_html.php?ip=12.215.42.19
1) http://api.hostip.info/get_html.php?ip=12.215.42.19
2)
2)
$json = file_get_contents('http://freegeoip.appspot.com/json/66.102.13.106');
$expression = json_decode($json);
print_r($expression);
回答by Absolute?ER?
Check out php-ip-2-countryfrom code.google. The database they provide is updated daily, so it is not necessary to connect to an outside server for the check if you host your own SQL server. So using the code you would only have to type:
从 code.google 中查看php-ip-2-country。他们提供的数据库每天更新，因此如果您托管自己的 SQL 服务器，则无需连接到外部服务器进行检查。所以使用代码你只需要输入：
<?php
$ip = $_SERVER['REMOTE_ADDR'];
if(!empty($ip)){
require('./phpip2country.class.php');
/**
* Newest data (SQL) avaliable on project website
* @link http://code.google.com/p/php-ip-2-country/
*/
$dbConfigArray = array(
'host' => 'localhost', //example host name
'port' => 3306, //3306 -default mysql port number
'dbName' => 'ip_to_country', //example db name
'dbUserName' => 'ip_to_country', //example user name
'dbUserPassword' => 'QrDB9Y8CKMdLDH8Q', //example user password
'tableName' => 'ip_to_country', //example table name
);
$phpIp2Country = new phpIp2Country($ip,$dbConfigArray);
$country = $phpIp2Country->getInfo(IP_COUNTRY_NAME);
echo $country;
?>
Example Code(from the resource)
示例代码（来自资源）
<?
require('phpip2country.class.php');
$dbConfigArray = array(
'host' => 'localhost', //example host name
'port' => 3306, //3306 -default mysql port number
'dbName' => 'ip_to_country', //example db name
'dbUserName' => 'ip_to_country', //example user name
'dbUserPassword' => 'QrDB9Y8CKMdLDH8Q', //example user password
'tableName' => 'ip_to_country', //example table name
);
$phpIp2Country = new phpIp2Country('213.180.138.148',$dbConfigArray);
print_r($phpIp2Country->getInfo(IP_INFO));
?>
Output
输出
Array
(
[IP_FROM] => 3585376256
[IP_TO] => 3585384447
[REGISTRY] => RIPE
[ASSIGNED] => 948758400
[CTRY] => PL
[CNTRY] => POL
[COUNTRY] => POLAND
[IP_STR] => 213.180.138.148
[IP_VALUE] => 3585378964
[IP_FROM_STR] => 127.255.255.255
[IP_TO_STR] => 127.255.255.255
)
回答by Ram Sharma
We can use geobytes.com to get the location using user IP address
我们可以使用 geobytes.com 使用用户 IP 地址获取位置
$user_ip = getIP();
$meta_tags = get_meta_tags('http://www.geobytes.com/IPLocator.htm?GetLocation&template=php3.txt&IPAddress=' . $user_ip);
echo '<pre>';
print_r($meta_tags);
it will return data like this
它会返回这样的数据
Array(
[known] => true
[locationcode] => USCALANG
[fips104] => US
[iso2] => US
[iso3] => USA
[ison] => 840
[internet] => US
[countryid] => 254
[country] => United States
[regionid] => 126
[region] => California
[regioncode] => CA
[adm1code] =>
[cityid] => 7275
[city] => Los Angeles
[latitude] => 34.0452
[longitude] => -118.2840
[timezone] => -08:00
[certainty] => 53
[mapbytesremaining] => Free
)
Function to get user IP
获取用户IP的函数
function getIP(){
if (isset($_SERVER["HTTP_X_FORWARDED_FOR"])){
$pattern = "/^(([1-9]?[0-9]|1[0-9]{2}|2[0-4][0-9]|25[0-5]).){3}([1-9]?[0-9]|1[0-9]{2}|2[0-4][0-9]|25[0-5])$/";
if(preg_match($pattern, $_SERVER["HTTP_X_FORWARDED_FOR"])){
$userIP = $_SERVER["HTTP_X_FORWARDED_FOR"];
}else{
$userIP = $_SERVER["REMOTE_ADDR"];
}
}
else{
$userIP = $_SERVER["REMOTE_ADDR"];
}
return $userIP;
}
回答by Sankar Jay
Try this simple one line code, You will get country and city of visitors from their ip remote address.
试试这个简单的一行代码，您将从他们的 ip 远程地址获得访问者的国家和城市。
$tags = get_meta_tags('http://www.geobytes.com/IpLocator.htm?GetLocation&template=php3.txt&IpAddress=' . $_SERVER['REMOTE_ADDR']);
echo $tags['country'];
echo $tags['city'];
回答by Halayem Anis
You can use a web-service from http://ip-api.com
in your php code, do as follow :
您可以
在 php 代码中使用来自http://ip-api.com的网络服务
，请执行以下操作：
<?php
$ip = $_REQUEST['REMOTE_ADDR']; // the IP address to query
$query = @unserialize(file_get_contents('http://ip-api.com/php/'.$ip));
if($query && $query['status'] == 'success') {
echo 'Hello visitor from '.$query['country'].', '.$query['city'].'!';
} else {
echo 'Unable to get location';
}
?>
the query have many other informations:
查询还有许多其他信息：
array (
'status' => 'success',
'country' => 'COUNTRY',
'countryCode' => 'COUNTRY CODE',
'region' => 'REGION CODE',
'regionName' => 'REGION NAME',
'city' => 'CITY',
'zip' => ZIP CODE,
'lat' => LATITUDE,
'lon' => LONGITUDE,
'timezone' => 'TIME ZONE',
'isp' => 'ISP NAME',
'org' => 'ORGANIZATION NAME',
'as' => 'AS NUMBER / NAME',
'query' => 'IP ADDRESS USED FOR QUERY',
)
