在 bash 中连接两个没有换行符的命令的输出
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Concatenate in bash the output of two commands without newline character
提问by synaptik
What I need:
我需要的：
Suppose I have two commands, Aand B, each of which returns a single-line string (i.e., a string with no newline character, except possibly 1 at the very end). I need a command (or sequence of piped commands) Cthat concatenates the output of commands Aand Bon the same line and inserts 1 space character between them.
假设我有两个命令，A和B，每个都返回一个单行字符串（即，一个没有换行符的字符串，除了最后可能是 1）。我需要一个命令（或管道的命令序列）C该串接命令的输出A和B在同一行上并插入它们之间的1个空格字符。
Example of how it should work:
它应该如何工作的示例：
For example, suppose the output of command Ais the string betweenthe quotation marks here:
例如，假设 command 的输出A是这里引号之间的字符串：
"The quick"
And suppose the output of command Bis the string betweenthe quotation marks here:
并假设 command 的输出B是此处引号之间的字符串：
"brown fox"
Then I want the output of command(s) Cto be the string betweenthe quotation marks here:
然后我希望命令的输出是这里引号之间的C字符串：
"The quick brown fox"
My best attempted solution:
我最好的尝试解决方案：
In trying to figure out Cby myself, it seemed that the follow sequence of piped commands should work:
在试图自己弄清楚时C，以下管道命令序列似乎应该起作用：
{ echo "The quick" ; echo "brown fox" ; } | xargs -I{} echo {} | sed 's/\n//'
Unfortunately, the output of this command is
不幸的是，这个命令的输出是
The quick
brown fox
回答by anubhava
You can use tr:
您可以使用tr：
{ echo "The quick"; echo "brown fox"; } | tr "\n" " "
OR using sed:
或使用 sed：
{ echo "The quick"; echo "brown fox"; } | sed ':a;N;s/\n/ /;ba'
OUTPUT:
输出：
The quick brown fox
回答by Mat
echo "$(A)" "$(B)"
should work assuming that neither Anor Boutput multiple lines.
应该工作假设既不A也不B输出多行。
$ echo "$(echo "The quick")" "$(echo "brown fox")"
The quick brown fox
回答by chepner
$ commandA () { echo "The quick"; }
$ commandB () { echo "brown fox"; }
$ x="$(commandA) $(commandB)"
$ echo "$x"
The quick brown fox
回答by hemanto
I'll try to explain the solution with another simple example
我将尝试用另一个简单的例子来解释解决方案
We've to concatenate the output of the following command:
"pwd" and "ls"
我们必须连接以下命令的输出：
“pwd”和“ls”
echo "$(pwd)$(ls)";
Output: 2 concatenated strings
输出：2个连接的字符串
回答by Lirux
$ { echo -n "The quick" ; echo -n " " ; echo "brown fox" ; }
The quick brown fox
