bash Bash正则表达式在句子中查找特定单词
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Bash regex finding particular words in a sentence
提问by JDS
I have a sentence like this:
我有这样一句话：
"The dog jumped over the moon because he likes jumping"
And I want to find all words that match jump.*, i.e. jumpedand jumping. How can I do this?
我想找到所有匹配的单词jump.*，即jumped和jumping。我怎样才能做到这一点？
Currently I have the sentence in a variable, $sentence. And I know the match word that I want to test against, e.g. $testis jump.
目前我有一个变量中的句子，$sentence. 而且我知道我要测试的匹配词，例如$test是jump.
Thank you
谢谢
采纳答案by morja
回答by Todd A. Jacobs
A Pipe-Free Bash Solution
无管道 Bash 解决方案
If you want to do this purely in Bash, you can use the regular expression matching operator and the built-in BASH_REMATCHvariable to hold the results. For example:
如果你想纯粹在 Bash 中做到这一点，你可以使用正则表达式匹配运算符和内置的BASH_REMATCH变量来保存结果。例如：
re='\bjump[[:alpha:]]*\b'
string="The dog jumped over the moon because he likes jumping"
for word in $string; do
[[ "$word" =~ $re ]] && echo "${BASH_REMATCH}"
done
Given your corpus, this correctly returns the following results:
鉴于您的语料库，这将正确返回以下结果：
jumped
jumping
回答by William Pursell
echo $sentence | tr ' ' '\n' | grep "^$test"
To be more thorough:
更彻底：
echo $sentence | tr '[[:space:]]' '\n' | grep "^$test"
回答by Clay
http://www.linuxjournal.com/content/bash-regular-expressions
http://www.linuxjournal.com/content/bash-regular-expressions
looks like it might help you. (I'm no good at regex or bash, sorry)
看起来它可能对你有帮助。（我不擅长正则表达式或 bash，抱歉）
