pandas 熊猫图未在 ipython 笔记本中显示为内联
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pandas plot doesn't show in ipython notebook as inline
提问by HMPark
I'm trying to plot graph in ipython notebook inline, but .plot()methos just shows the object information, as
我试图在 ipython notebook 中内联绘制图形，但.plot()方法只显示对象信息，如
<matplotlib.axes._subplots.AxesSubplot at 0x10d8740d0>
but no graph. also i could make it show graph with plt.show(), but i want do it inline. so i tryed %matplotlib inlineand ipython notebook --matplotlib=inline, but it was no helpful.
但没有图表。我也可以让它显示图形plt.show()，但我想内联。所以我尝试了%matplotlib inline和ipython notebook --matplotlib=inline，但没有帮助。
If i use %matplotlib inline, then .plot()shows
如果我使用%matplotlib inline，则.plot()显示
/Users/<username>/Library/Enthought/Canopy_64bit/User/lib/python2.7/site-packages/IPython/core/formatters.py:239:
FormatterWarning: Exception in image/png formatter: 'ascii' codec can't decode byte 0xe2 in position 0: ordinal not in range(128) FormatterWarning,
and using ipython notebook --matplotlib=inlineshows same.
并使用ipython notebook --matplotlib=inline显示相同。
采纳答案by aus_lacy
Change
改变
ipython notebook --matplotlib=inline
to
到
ipython notebook --matplotlib inline
Notice no =sign.
注意没有=标志。
回答by Robert Smith
I will give you an example based on my comment above:
我将根据我上面的评论给你一个例子：
You have something like this:
你有这样的事情：
import matplotlib.pyplot as plt
%matplotlib inline
legend = "\xe2"
plt.plot(range(5), range(5))
plt.legend([legend])
which results in:
这导致：
UnicodeDecodeError: 'ascii' codec can't decode byte 0xe2 in position 0: ordinal not in range(128)
As I said, this is because matplotlib wants to use strings of type unicode. So, in the process of plotting, matplotlib tries to decode your string to convert it to unicode using decode. However, decodehas asciias default encoding, and since your character doesn't belong to ascii, an error is shown. The solution is to decode the string yourself with the appropriate encoding:
正如我所说，这是因为 matplotlib 想要使用类型为 的字符串unicode。因此，在绘图过程中，matplotlib 尝试解码您的字符串以使用decode. 但是，decode具有ascii默认编码，并且由于您的字符不属于ascii，因此会显示错误。解决方案是使用适当的编码自己解码字符串：
import matplotlib.pyplot as plt
%matplotlib inline
legend = "\xe2".decode(encoding='latin-1')
plt.plot(range(5), range(5))
plt.legend([legend])
By the way, regarding the use ipython notebook --matplotlib inline, it is considered bad practice to do that because you are hiding what you did in order to obtain the resulting notebook. It is much better to include %matplotlib inlinein your notebook.
顺便说一句，关于 use ipython notebook --matplotlib inline，这样做被认为是不好的做法，因为您隐藏了为了获得结果笔记本所做的事情。最好包含%matplotlib inline在您的笔记本中。
回答by HMPark
Thanks for all your helps. i've tried all of above, but did't work.
感谢您的所有帮助。我已经尝试了以上所有方法，但没有奏效。
here i found that was bug in fontmanager.pyin matplotlib 1.4.x, fixed with thisdevelopment version of matplotlib and it worked.
在这里我发现这是fontmanager.pymatplotlib 1.4.x 中的错误，使用 matplotlib 的这个开发版本修复并且它起作用了。
i'm so sorry that i couldn't find it earlier. thanks for all of you.
很抱歉我没能早点找到它。谢谢大家。
