如何使用 XSLT 在 XML 中设置属性？
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How to set attribute in XML using XSLT?
提问by VextoR
For example, I want to add an attribute to this node:
例如，我想向这个节点添加一个属性：
<Party>
So it will look like:
所以它看起来像：
<Party role="this should be set using XPath">
Attribute value has to come from XPath.
属性值必须来自 XPath。
The following will not work :)
以下将不起作用:)
<Party role=<xsl:value-of select="some/xpath/path"/>>
How to do that?
怎么做？
回答by Ian Roberts
Attributes of literal result elements support the attribute value templatesyntax, using {}:
文字结果元素的属性支持属性值模板语法，使用{}：
<Party role="{some/xpath/path}">
回答by Martin Honnen
<xsl:template match="Party">
<Party role="{some/xpath/path}">
<xsl:apply-templates select="@* | node()"/>
</Party>
</xsl:template>
should do. As an alternative
应该做。作为备选
<xsl:template match="Party">
<xsl:copy>
<xsl:attribute name="role" select="some/xpath/path"/>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
Of course the apply-templates is only necessary if there are attribute and/or child nodes you also want to be processed (for example to be copied by an identity transformation template).
当然，仅当您还希望处理属性和/或子节点（例如，由身份转换模板复制）时，才需要应用模板。
回答by Shanjee
you can try the below sample:
您可以尝试以下示例：
<xsl:for-each select="YOUR_SELECT_PATH">
<a>
<Party> <xsl:attribute name="role"><xsl:value-of select="@source"/></xsl:attribute> </Party>
<xsl:value-of select="."/>
</a>
</xsl:for-each>
Here I am setting the attribute role to a xml node Party.
这里我将属性角色设置为 xml 节点 Party。
