php Yii 框架：控制器/动作 url 和参数
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Yii framework: Controller/Action url & parameters
提问by Peterim
In my application , I have ApiControllerwith actionUsers, So in YII the path becomes api/users. Now in order to get certain users info , I use the following path api/users/id/10where 10 is the userID and idpart of the path is basically a GET parameter (api/users?id=10).
在我的应用程序，我ApiController用actionUsers，所以在YII的路径变得api/users。现在为了获取某些用户信息，我使用以下路径api/users/id/10，其中 10 是用户 ID，id路径的一部分基本上是 GET 参数 ( api/users?id=10)。
Is there any way to do the same thing without idpart of the path, i.e. I want my path to look like api/users/10?
有没有办法在没有id路径的情况下做同样的事情，即我希望我的路径看起来像api/users/10？
Thank you!
谢谢！
回答by Shiki
You're going to need to put in rule patterns in the urlManager component:
您将需要在 urlManager 组件中放入规则模式：
Yii Framework Documentation: url
Your config should look something like this:
你的配置应该是这样的：
array(
......
'components'=>array(
......
'urlManager'=>array(
'urlFormat'=>'path',
'rules'=>array(
'api/users/<id>'=>'api/users',
),
),
),
);
You can then get the value by:
然后，您可以通过以下方式获取值：
$id = Yii::app()->getRequest()->getQuery('id');
回答by killlinuxkill
Try This......
尝试这个......
$id = Yii::app()->request->getParam('id');
回答by Manoj Kumar
in addition to @shiki's answer you can also do this
除了@shiki的回答，你也可以这样做
array(
......
'components'=>array(
......
'urlManager'=>array(
'urlFormat'=>'path',
'rules'=>array(
'api/users/<id>'=>'api/users',
),
),
),
);
and in action
并在行动
public function actionUsers($id=null) // argument variable should same as in urlmanager
{
echo $id;
}
