使用一维数组编写 Java 程序。有一个包含 10 个数字的列表并根据索引获取一个值
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Write a Java program using single dimensional array. Have a list of 10 numbers and fetch a value based on the index
提问by Programming Noob
So I have this assignment for my Programming class, and I'm lost on what to do for the second part. This is the code I have so far:
所以我的编程课有这个作业，我不知道第二部分该做什么。这是我到目前为止的代码：
class SingleArray
{
public static void main(String[]args)
{
int[] b=new int[]{5,10,15,20,25,30,35,40,45,50};
Not much I know, but I really am confused on how I would get it to fetch the different array values. Do I have to import the util scanner to do this? Any help to point me in the right direction? Thanks guys!
我知道的不多，但我真的很困惑如何让它获取不同的数组值。我是否必须导入 util 扫描程序才能执行此操作？任何帮助我指出正确的方向？多谢你们！
回答by Steve P.
To access an index iin int[] b, you use: b[i]. For example:
要访问索引i中int[] b，您可以使用：b[i]。例如：
System.out.println(b[i]); //prints the int at index i
b[i] = 5; //assigns 5 to index i
b[i] = x; //assigns an int x, to index i
int y = b[i]; //assigns b[i] to y
To search through the array for a number x:
要在数组中搜索数字x：
for (int i = 0; i < b.length; i++)
{
if (b[i] == x)
{
//doSomething
}
}
There are also auxiliary methods provided by the Java Arraysclass.
Java Arrays类还提供了一些辅助方法。
Here's a tutorial on arrays, here's an additional Java Language Basics tutorial.
这是关于数组的教程，这是附加的Java 语言基础教程。
回答by Sajal Dutta
Please do the assignments in the comments below-
请在下面的评论中完成任务-
class SingleArray {
// Declare an array of 10 integers.
// Assignment: Why did I declare it as static?
private static int[] array = new int[] { 5, 10, 15, 20, 25, 30, 35, 40, 45, 50 };
// A method that returns the value at a given index from the array
// Assignment: Why the method below is static?
private static int getValue(int index){
return array[index];
}
public static void main(String[] args){
for (int i = 0; i < array.length; i++){
int valueAtIndex = getValue(i);
System.out.println("Index: " + (i + 1) + " Value: " + valueAtIndex);
// Assignment: remove the statement "int valueAtIndex = getValue(i);" and
// modify the System.out.println statement to have the same result
}
}
}
回答by ihsan kocak
List<Integer> integerList=new ArrayList<Integer>();
for(int i=0;i<10;i++){
integerList.add(i);
}
//you can fetch the values by using this method:
integerList.get(valueIndex);
回答by Pratibh Acharya
This might help:
这可能有帮助：
public class OneDimensionalArrays {
public static void main(String[] args) {
//initialize an array num with the respective values
int []num={5,10,15,20,25,30,35,40,45,50};
// The looping will work within the range of the array.
for (int i = 0; i<num.length;i++){
System.out.println("Enter the index to find the value of ");
//To catch array index out of bound exception
try{
Scanner sc = new Scanner(System.in);
//Save the user inputted value in indexValue variable
int indexValue = sc.nextInt();
// Enter 100 to terminate the program execution
if (indexValue != 100) {
System.out.println("Value in the respective index of array is " + num[indexValue]);
}
else{
System.out.println("Program has been terminated by user");
break;
}
}
catch (Exception e ){
System.out.println("Enter the index within range of the array");
}
}
}
}
