在 Objective-C 中将 NSArray 转换为 NSString

Convert NSArray to NSString in Objective-C

提问by alexyorke

I am wondering how to convert an NSArray[@"Apple", @"Pear ", 323, @"Orange"]to a string in Objective-C.

我想知道如何在Objective-C中将NSArray转换[@"Apple", @"Pear ", 323, @"Orange"]为字符串。

回答by Dave DeLong

NSString * result = [[array valueForKey:@"description"] componentsJoinedByString:@""];

回答by Jason

One approach would be to iterate over the array, calling the descriptionmessage on each item:

一种方法是遍历数组，description在每个项目上调用消息：

NSMutableString * result = [[NSMutableString alloc] init];
for (NSObject * obj in array)
{
    [result appendString:[obj description]];
}
NSLog(@"The concatenated string is %@", result);

Another approach would be to do something based on each item's class:

另一种方法是根据每个项目的类做一些事情：

NSMutableString * result = [[NSMutableString alloc] init];
for (NSObject * obj in array)
{
    if ([obj isKindOfClass:[NSNumber class]])
    {
        // append something
    }
    else
    {
        [result appendString:[obj description]];
    }
}
NSLog(@"The concatenated string is %@", result);

If you want commas and other extraneous information, you can just do:

如果你想要逗号和其他无关信息，你可以这样做：

NSString * result = [array description];

回答by Pranay

I think Sanjay's answer was almost there but i used it this way

我认为 Sanjay 的回答差不多了，但我是这样用的

NSArray *myArray = [[NSArray alloc] initWithObjects:@"Hello",@"World", nil];
NSString *greeting = [myArray componentsJoinedByString:@" "];
NSLog(@"%@",greeting);

Output :

输出 ：

2015-01-25 08:47:14.830 StringTest[11639:394302] Hello World

As Sanjay had hinted - I used method componentsJoinedByStringfrom NSArray that does joining and gives you back NSString

正如 Sanjay 所暗示的那样 - 我使用了 NSArray 中的componentsJoinedByString方法来加入并返回NSString

BTW NSStringhas reverse method componentsSeparatedByStringthat does the splitting and gives you NSArrayback .

顺便说一句，NSString具有反向方法componentsSeparatedByString进行拆分并返回NSArray。

回答by MarkP

I recently found a really good tutorial on Objective-C Strings:

我最近发现了一个关于 Objective-C 字符串的非常好的教程：

http://ios-blog.co.uk/tutorials/objective-c-strings-a-guide-for-beginners/

http://ios-blog.co.uk/tutorials/objective-c-strings-a-guide-for-beginners/

And I thought that this might be of interest:

我认为这可能很有趣：

If you want to split the string into an array use a method called componentsSeparatedByString to achieve this:

如果要将字符串拆分为数组，请使用称为 componentsSeparatedByString 的方法来实现此目的：

NSString *yourString = @"This is a test string";
    NSArray *yourWords = [myString componentsSeparatedByString:@" "];

    // yourWords is now: [@"This", @"is", @"a", @"test", @"string"]

if you need to split on a set of several different characters, use NSString's componentsSeparatedByCharactersInSet:

如果您需要拆分一组不同的字符，请使用 NSString 的 componentsSeparatedByCharactersInSet：

NSString *yourString = @"Foo-bar/iOS-Blog";
NSArray *yourWords = [myString componentsSeparatedByCharactersInSet:
                  [NSCharacterSet characterSetWithCharactersInString:@"-/"]
                ];

// yourWords is now: [@"Foo", @"bar", @"iOS", @"Blog"]

Note however that the separator string can't be blank. If you need to separate a string into its individual characters, just loop through the length of the string and convert each char into a new string:

但请注意，分隔符字符串不能为空。如果您需要将一个字符串分成单独的字符，只需遍历字符串的长度并将每个字符转换为一个新字符串：

NSMutableArray *characters = [[NSMutableArray alloc] initWithCapacity:[myString length]];
for (int i=0; i < [myString length]; i++) {
    NSString *ichar  = [NSString stringWithFormat:@"%c", [myString characterAtIndex:i]];
    [characters addObject:ichar];
}

回答by Sanjay Kakadiya

NSString * str = [componentsJoinedByString:@""];

and you have dic or multiple array then used bellow

并且您有 dic 或多个数组，然后在下面使用

NSString * result = [[array valueForKey:@"description"] componentsJoinedByString:@""];   

回答by AbdulAziz Rustam Ogli

NSArray *array = [NSArray arrayWithObjects:@"One",@"Two",@"Three", nil];
NSString *stringFromArray = [array componentsJoinedByString:@" "];

The first line initializes an array with objects. The second line joins all elements of that array by adding the string inside the "" and returns a string.

第一行用对象初始化一个数组。第二行通过在 "" 内添加字符串来连接该数组的所有元素，并返回一个字符串。

回答by Asad Ali Choudhry

Objective C Solution

目标 C 解决方案

NSArray * array = @[@"1", @"2", @"3"];
NSString * stringFromArray = [[array valueForKey:@"description"] componentsJoinedByString:@"-"];   // "1-2-3"

Those who are looking for a solution in Swift

那些正在寻找解决方案的人 Swift

If the array contains strings, you can use the String's join method:

如果数组包含字符串，则可以使用 String 的 join 方法：

var array = ["1", "2", "3"]

let stringFromArray = "-".join(array) // "1-2-3"

In Swift 2:

在 Swift 2 中：

var array = ["1", "2", "3"]

let stringFromArray = array.joinWithSeparator("-") // "1-2-3"

In Swift 3 & 4

在斯威夫特 3 和 4 中

var array = ["1", "2", "3"]

let stringFromArray = array.joined(separator: "-") // "1-2-3"

回答by jasmo2

The way I know is easy.

我知道的方法很简单。

var NSArray_variable = NSArray_Object[n]
var stringVarible = NSArray_variable as String

nis the inner position in the array This in SWIFT Language. It might work in Objective C

n是数组中的内部位置 This 在 SWIFT 语言中。它可能适用于目标 C

回答by AhmedZah

Swift 3.0 solution:

Swift 3.0 解决方案：

let string = array.joined(separator: " ")