java 如何仅根据数字、点和逗号过滤字符串？
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How do I filter a string on just numbers, dots and commas?
提问by truy37
Okay, so ive got a long string, and I want to remove everything thats inside, except for decimal numbers, comma's and dots,
好的，所以我有一个很长的字符串，我想删除里面的所有内容，除了十进制数字、逗号和点，
I have tried:
我努力了：
str = str.replace("[^0-9\.\,]","");
But this just ends up in nothing..
但这最终一无所获..
Can anyone help me?
谁能帮我？
Thanks!
谢谢！
回答by jjnguy
You don't need to escape the characters in the character group. You should also be using replaceAll().
您不需要对字符组中的字符进行转义。您还应该使用replaceAll().
str = str.replaceAll("[^0-9.,]+","");
回答by Martijn
Try str.replaceAll("[^0-9.,]+","");
尝试 str.replaceAll("[^0-9.,]+","");
