wpf 如何以编程方式设置样式
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时间：2020-09-08 21:55:06 来源:igfitidea点击:
How to set the style programmatically
提问by user384080
I have the following style but i need to make it programmatically:
我有以下风格，但我需要以编程方式制作：
<xcdg:DataGridControl MinHeight="300"
Name="listViewUnallocated"
ItemsSource="{Binding Source={StaticResource
cvs_unallocatedTerminals}}"
AllowDrop="True"
Drop="Grid_Drop"
MouseMove="Grid_MouseMove"
KeyUp="listViewUnallocated_KeyUp"
MouseDoubleClick="gridUnallocated_MouseDoubleClick"
ReadOnly="True"
DockPanel.Dock="Top">
<xcdg:DataGridControl.Resources>
<Style TargetType="{x:Type xcdg:DataRow}" x:Name="selectedStyleTrigger">
<Style.Triggers>
<DataTrigger Binding="{Binding TerminalId}" Value="72948028">
<Setter Property="Background" Value="Red" />
</DataTrigger>
</Style.Triggers>
</Style>
</xcdg:DataGridControl.Resources>
回答by Grant Thomas
In the code-behind file of the control, try:
在控件的代码隐藏文件中，尝试：
this.Style = Resources["ResourceName"] as Style;
回答by Mangesh
Set x:Keyin XAML & in code-behind use:
设置x:Key在XAML和代码隐藏使用：
something.Style = (Style) FindResource("YourResourceKey");
回答by Vishwash Roy
Hi we can set style programmatically like this.
嗨，我们可以像这样以编程方式设置样式。
Style rowStyle = new Style(typeof(DataGridRow));
DataTrigger dataTrigger = new DataTrigger("TerminalId");
Binding binding = new Binding();
dataTrigger.Binding = binding;
dataTrigger.Value = 72948028;
Setter setter = new Setter(DataGridRow.BackgroundProperty, Brushes.Red);
dataTrigger.Setters.Add(setter);
rowStyle.Triggers.Add(dataTrigger);
listViewUnallocated.RowStyle = rowStyle;
