如何使用 Java 将 Zip 文件中的文件读取到内存中？
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How can I read files from Zip file to memory with Java?
提问by newbie
I found example from SUN site (http://java.sun.com/developer/technicalArticles/Programming/compression/), but it returns BufferedOutputStream. But I would like to get ZipEntry file as InputStream and then process next file. Is that possible? My program has no access to harddisk, so it cannot even temporarily save files.
我从 SUN 站点 (http://java.sun.com/developer/technicalArticles/Programming/compression/) 中找到了示例，但它返回了 BufferedOutputStream。但我想将 ZipEntry 文件作为 InputStream 获取，然后处理下一个文件。那可能吗？我的程序无法访问硬盘，因此它甚至无法临时保存文件。
import java.io.*;
import java.util.zip.*;
public class UnZip {
final int BUFFER = 2048;
public static void main (String argv[]) {
try {
BufferedOutputStream dest = null;
FileInputStream fis = new
FileInputStream(argv[0]);
ZipInputStream zis = new
ZipInputStream(new BufferedInputStream(fis));
ZipEntry entry;
while((entry = zis.getNextEntry()) != null) {
System.out.println("Extracting: " +entry);
int count;
byte data[] = new byte[BUFFER];
// write the files to the disk
FileOutputStream fos = new
FileOutputStream(entry.getName());
dest = new
BufferedOutputStream(fos, BUFFER);
while ((count = zis.read(data, 0, BUFFER))
!= -1) {
dest.write(data, 0, count);
}
dest.flush();
dest.close();
}
zis.close();
} catch(Exception e) {
e.printStackTrace();
}
}
}
回答by CodeCaster
Well, just change the part that writes the file into something you want to do with the data.
好吧，只需将写入文件的部分更改为您想要处理数据的部分。
while((entry = zis.getNextEntry()) != null) {
System.out.println("Extracting: " + entry);
int count;
byte[] data = new byte[BUFFER];
String filename = entry.getName();
System.out.println("Filename: " + filename);
while ((count = zis.read(data, 0, BUFFER)) != -1) {
// Do whatever you want with the data variable
System.out.println(data);
}
}
