C++ 中的右对齐输出流
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Right Justifying output stream in C++
提问by Matt Dunbar
I'm working in C++. I'm given a 10 digit string (char array) that may or may not have 3 dashes in it (making it up to 13 characters). Is there a built in way with the stream to right justify it?
我在 C++ 中工作。我得到一个 10 位字符串（字符数组），其中可能有也可能没有 3 个破折号（最多 13 个字符）。流是否有内置的方式来正确证明它？
How would I go about printing to the stream right justified? Is there a built in function/way to do this, or do I need to pad 3 spaces into the beginning of the character array?
我将如何正确地打印到流？是否有内置函数/方法来执行此操作，或者我是否需要在字符数组的开头填充 3 个空格？
I'm dealing with ostream to be specific, not sure if that matters.
我正在处理 ostream 的具体问题，不确定这是否重要。
回答by florin
You need to use std::setwin conjunction with std::right.
您需要std::setw与std::right.
#include <iostream>
#include <iomanip>
int main(void)
{
std::cout << std::right << std::setw(13) << "foobar" << std::endl;
return 0;
}
回答by NullUserException
Yes. You can use setw()to set the width. The default justification is right-justified, and the default padding is space, so this will add spaces to the left.
是的。您可以使用setw()来设置宽度。默认对齐是右对齐，默认填充是空格，所以这会在左边添加空格。
stream << setw(13) << yourString
See: setw(). You'll need to include <iomanip>.
见：setw()。您需要包括<iomanip>.
回答by Jollymorphic
See "setw" and "right" in your favorite C++ (iostream) reference for further details:
有关更多详细信息，请参阅您最喜欢的 C++ (iostream) 参考中的“setw”和“right”：
cout << setw(13) << right << your_string;
回答by demonkiller
You can avoid the std:: by typing
您可以通过键入来避免 std::
using namespace std;
after the header files
在头文件之后
