Linux GDB 检查内存权限
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GDB examine memory permissions
提问by viji
I've an address in memory and I want to find out the permissions (r/w/x) of that memory address.
我在内存中有一个地址，我想找出该内存地址的权限（r/w/x）。
E.g.
例如
char *s = "hello";
Here, the string literal "hello" is stored in read-only memory. When running the program through gdb, is there a possibility to check out the permissions for that memory address (whether only read is permitted or etc) ?
在这里，字符串文字“hello”存储在只读存储器中。通过 gdb 运行程序时，是否有可能检查该内存地址的权限（是否只允许读取等）？
采纳答案by Michael Foukarakis
You can first find where sis pointing to:
您可以先找到s指向的位置：
(gdb) print s
= 0x400dbc "foo"
and then find the section in which it's in:
然后找到它所在的部分：
(gdb) maintenance info sections
Exec file:
`/home/mfukar/tmp', file type elf64-x86-64.
...sections...
0x00400db8->0x00400dfb at 0x00000db8: .rodata ALLOC LOAD READONLY DATA HAS_CONTENTS
...more sections...
and look for the READONLYflag.
并寻找READONLY旗帜。
Alternatively, look into /proc/PID/mapswhere PIDis the pid of the process you're debugging and you can get with info proc.
或者，查看您正在调试的进程的 pid/proc/PID/maps在哪里PID，您可以使用info proc.
