在 Python 中作为制表符分隔的列写入文本文件
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Writing into text file as tab separated columns in Python
提问by Ssank
I have two lists
我有两个清单
A = ["ATTTGTA", "ATTTGTA", "ATTTGTA", "ATTTGTA"]
A_modified = ["ATTGTA", "AAAT", "TTTA"]
I want an output tab separated txt file looking like
我想要一个输出制表符分隔的 txt 文件，看起来像
ATTTGTA ATTGTA
ATTTGTA AAAT
ATTTGTA TTTA
I tried the following piece of code but it does not write o/p in two columns, just as new rows each time
我尝试了下面的一段代码，但它没有在两列中写 o/p，就像每次都写新行
with open ('processed_seq.txt','a') as proc_seqf:
proc_seqf.write(A)
proc_seqf.write("\t")
proc_seqf.write(A_modified)
This is the output I get
这是我得到的输出
ATTTGTA
ATTGTA
ATTTGTA
AAAT
ATTTGTA
TTTA
采纳答案by Mihai Maruseac
You just need to pair the elements in the two list. You can do that using the zipfunction:
您只需要将两个列表中的元素配对即可。您可以使用以下zip功能来做到这一点：
with open ('processed_seq.txt','a') as proc_seqf:
for a, am in zip(A, A_modified):
proc_seqf.write("{}\t{}".format(a, am))
I have also used format(see specs) to format the string to get everything in a single line.
回答by gmas80
What about something like this? It provides you with some flexibility in input and output..
这样的事情怎么办？它为您提供了一些输入和输出的灵活性。
lines = [
['a', 'e', '7', '3'],
['b', 'f', '1', '5'],
['c', 'g', '2', '10'],
['d', 'h', '1', '14'],
]
def my_print( lns, spacing = 3 ):
widths = [max(len(value) for value in column) + spacing
for column in zip(*lines)]
proc_seqf = open('processed_seq.txt','a')
for line in lns:
pretty = ''.join('%-*s' % item for item in zip(widths, line))
print(pretty) # debugging print
proc_seqf.write(pretty + '\n')
return
my_print( lines )
I added the option that the user can decide the size of the spacing..
我添加了用户可以决定间距大小的选项..
To match with your example data:
要与您的示例数据匹配：
A = ["ATTTGTA", "ATTTGTA", "ATTTGTA", "ATTTGTA"]
A_modified = ["ATTGTA", "AAAT", "TTTA"]
lines = [ A, A_modified ]
回答by Kasramvd
If your lists are huge ,i suggest use itertools.cycle():
如果您的列表很大，我建议使用itertools.cycle()：
import itertools
ac=itertools.cycle(A)
a_mc=itertools.cycle(A_modified)
with open ('processed_seq.txt','a') as proc_seqf:
for i in A_modified:
proc_seqf.write("{}\t{}".format(ac.next(), a_mc.next()))
回答by Anzel
Apart from other great answers, as an alternative with try/exceptit will write all remaining elements in the list if their lengths are different (at least in your sample):
除了其他很棒的答案之外，try/except如果它们的长度不同（至少在您的示例中），它将在列表中写入所有剩余元素：
with open ('processed_seq.txt','w') as proc_seqf:
for each in range(max(len(A), len(A_modified))):
try:
proc_seqf.write("{}\t{}\n".format(A[each], A_modified[each]))
except IndexError:
if len(A) > len(A_modified):
proc_seqf.write("{}\t\n".format(A[each]))
else:
proc_seqf.write("\t{}\n".format(A_modified[each]))
cat processed_seq.txt
ATTTGTA ATTGTA
ATTTGTA AAAT
ATTTGTA TTTA
ATTTGTA
