C# 在集合中的项目上更改了可观察集合属性
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Observable Collection Property Changed on Item in the Collection
提问by Nate
I have an ObservableCollection<T>
. I've bound it to a ListBox control and I've added SortDescriptions
to the Items collection on the ListBox to make the list sort how I want.
我有一个ObservableCollection<T>
. 我已经将它绑定到一个 ListBox 控件,并且我已经添加SortDescriptions
到 ListBox 上的 Items 集合以使列表按照我想要的方式排序。
I want to resort the list at ANYpoint when any property changed on a child element.
当子元素上的任何属性发生更改时,我想在任何时候使用该列表。
All my child elements implement INotifyPropertyChanged
.
我所有的子元素都实现了INotifyPropertyChanged
.
采纳答案by micahtan
Brute force:
蛮力:
- Attach handler to each PropertyChanged event for each child item
- Grab the ListCollectionView from your CollectionViewSource
- Call Refresh.
- 将处理程序附加到每个子项的每个 PropertyChanged 事件
- 从 CollectionViewSource 中获取 ListCollectionView
- 呼叫刷新。
EDIT:
编辑:
The code for 1, 2 would live in your code-behind.
1、2 的代码将存在于您的代码隐藏中。
For #1, you'd do something like:
对于#1,您会执行以下操作:
private void Source_CollectionChanged(object sender, NotifyCollectionChangedEventArgs e)
{
switch (e.Action)
{
case NotifyCollectionChangedAction.Add:
foreach( SomeItem item in e.NewItems)
{
item.PropertyChanged += new PropertyChangedEventHandler(_SomeItem_PropertyChanged);
}
break;
....
**HANDLE OTHER CASES HERE**
....
}
}
For #2, in your CollectionChanged handler, you would do something like:
对于#2,在您的 CollectionChanged 处理程序中,您将执行以下操作:
private void _SomeItem_PropertyChanged(object sender, PropertyChangedEventArgs e)
{
ListCollectionView lcv = (ListCollectionView)(CollectionViewSource.GetDefaultView(theListBox.ItemsSource));
lcv.Refresh();
}
EDIT2: However, in this case, I would stronglysuggest that you also check ListCollectionView.NeedsRefresh and only refresh if that is set. There's no reason to re-sort if your properties have changed which don't affect the sort.
EDIT2:但是,在这种情况下,我强烈建议您还检查 ListCollectionView.NeedsRefresh 并且仅在设置时刷新。如果您的属性发生了不影响排序的更改,则没有理由重新排序。
回答by apandit
This works. Whenever the collection changes, it re-sorts the collection. Might be doable in a more efficient way but this is the gist of it.
这有效。每当集合更改时,它都会重新排序集合。可能以更有效的方式可行,但这是它的要点。
public partial class TestWindow : Window {
ObservableCollection<TestClass> oc;
public TestWindow() {
InitializeComponent();
// Fill in the OC for testing
oc = new ObservableCollection<TestClass>();
foreach( char c in "abcdefghieeddjko" ) {
oc.Add( new TestClass( c.ToString(), c.ToString(), c.GetHashCode() ) );
}
lstbox.ItemsSource = oc;
// Set up the sorting (this is how you did it.. doesn't work)
lstbox.Items.SortDescriptions.Add( new SortDescription("A", ListSortDirection.Ascending) );
// This is how we're going to do it
oc.CollectionChanged += new System.Collections.Specialized.NotifyCollectionChangedEventHandler( oc_Sort );
}
void oc_Sort( object sender, System.Collections.Specialized.NotifyCollectionChangedEventArgs e ) {
// This sorts the oc and returns IEnumerable
var items = oc.OrderBy<TestClass, int>( ( x ) => ( x.C ) );
// Rest converst IEnumerable back to OC and assigns it
ObservableCollection<TestClass> temp = new ObservableCollection<TestClass>();
foreach( var item in items ) {
temp.Add( item );
}
oc = temp;
}
private void Button_Click( object sender, RoutedEventArgs e ) {
string a = "grrrr";
string b = "ddddd";
int c = 383857;
oc.Add( new TestClass( a, b, c ) );
}
}
public class TestClass : INotifyPropertyChanged {
private string a;
private string b;
private int c;
public TestClass( string f, string g, int i ) {
a = f;
b = g;
c = i;
}
public string A {
get { return a; }
set { a = value; OnPropertyChanged( "A" ); }
}
public string B {
get { return b; }
set { b = value; OnPropertyChanged( "B" ); }
}
public int C {
get { return c; }
set { c = value; OnPropertyChanged( "C" ); }
}
#region onpropertychanged
public event PropertyChangedEventHandler PropertyChanged;
protected void OnPropertyChanged( string propertyName ) {
if( this.PropertyChanged != null ) {
PropertyChanged( this, new PropertyChangedEventArgs( propertyName ) );
}
}
#endregion
}
XAML:
XAML:
<Window x:Class="ServiceManager.TestWindow" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" Title="TestWindow" Height="500" Width="500"> <DockPanel> <ListBox ItemsSource="{Binding}" x:Name="lstbox"> <ListBox.ItemTemplate> <DataTemplate> <StackPanel Orientation="Horizontal"> <Label Content="{Binding Path=A}"/> <Label Content="{Binding Path=B}"/> <Label Content="{Binding Path=C}"/> </StackPanel> </DataTemplate> </ListBox.ItemTemplate> </ListBox> <Button Click="Button_Click" Content="Click" /> </DockPanel> </Window>