C++ 使用 new 运算符初始化数组
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Use new operator to initialise an array
提问by lilroo
I want to initialise an array in the format that uses commas to separate the elements surrounded in curly braces e.g:
我想以使用逗号分隔花括号中的元素的格式初始化数组，例如：
int array[10]={1,2,3,4,5,6,7,8,9,10};
However, I need to use the new operator to allocate the memory e.g:
但是，我需要使用 new 运算符来分配内存，例如：
int *array = new int[10];
Is there a way to combine theses methods so that I can allocate the memory using the new operator and initialise the array with the curly braces ?
有没有办法组合这些方法，以便我可以使用 new 运算符分配内存并使用花括号初始化数组？
采纳答案by Luchian Grigore
You can use memcpyafter the allocation.
memcpy配置好后就可以使用了。
int originalArray[] ={1,2,3,4,5,6,7,8,9,10};
int *array = new int[10];
memcpy(array, originalArray, 10*sizeof(int) );
I'm not aware of any syntax that lets you do this automagically.
我不知道有任何语法可以让您自动执行此操作。
Much later edit:
很久以后编辑：
const int *array = new int[10]{1,2,3,4,5,6,7,8,9,10};
回答by jogojapan
In the new Standard for C++ (C++11), you can do this:
在新的 C++ 标准 (C++11) 中，您可以这样做：
int* a = new int[10] { 1,2,3,4,5,6,7,8,9,10 };
It's called an initializer list. But in previous versions of the standard that was not possible.
它被称为初始化列表。但是在以前版本的标准中这是不可能的。
The relevant online reference with further details (and very hard to read) is here. I also tried it using GCC and the --std=c++0xoption and confirmed that it works indeed.
包含更多详细信息（并且很难阅读）的相关在线参考资料在这里。我还使用 GCC 和--std=c++0x选项进行了尝试，并确认它确实有效。
