如何从java rest api返回json对象
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how to return json objects from java rest api
提问by Eduardo Dennis
I am trying to return a JSON object from a jax-rs but I get an internal server error whenever I try to access.
我正在尝试从 jax-rs 返回一个 JSON 对象，但是每当我尝试访问时都会收到内部服务器错误。
This is my method, I am using javax.ws.rs.GET.
这是我的方法，我正在使用javax.ws.rs.GET.
@GET
@Produces("application/json")
public Testy getJson() {
return new Testy("hello");
}
This is the class:
这是课程：
public class Testy {
private final String value;
public Testy(String value){
this.value = value;
}
public String getValue(){
return value;
}
}
My Pom.xml has this dependency, I have tried various dependencies, but none work. There are various maven resources for jersey, there's jersey-client jersey-core.
我的 Pom.xml 有这个依赖项，我尝试了各种依赖项，但都没有工作。jersey 有各种 maven 资源，有 jersey-client jersey-core。
<dependency>
<groupId>com.fasterxml.Hymanson.jaxrs</groupId>
<artifactId>Hymanson-jaxrs-json-provider</artifactId>
<version>2.3.3</version>
</dependency>
I am using Glassfish 4.
我正在使用 Glassfish 4。
Questions about working with Jersey:
关于与泽西岛合作的问题：
I have seen some placeswhere they mention you need to have initialize POJO support, it seems like its for jersey 1.* but I am not sure. I don't need this if I am using 2.* ?
我看过一些地方，他们提到您需要初始化 POJO 支持，这似乎是针对球衣 1.* 的，但我不确定。如果我使用 2.* ，我不需要这个？
Do I have to modify the web.xml to point to the jersey servlet ?
我是否必须修改 web.xml 以指向球衣 servlet？
How can I produce and consume JSON objects using POJO classes !?
如何使用 POJO 类生成和使用 JSON 对象！？
Edit
编辑
Here is my auto generated config class.
这是我自动生成的配置类。
采纳答案by Eduardo Dennis
I had to add the HymansonFeature resource to my ApplicationConfig Class.
我必须将 HymansonFeature 资源添加到我的 ApplicationConfig 类中。
@javax.ws.rs.ApplicationPath("webresources")
public class ApplicationConfig extends Application {
@Override
public Set<Class<?>> getClasses() {
Set<Class<?>> resources = new java.util.HashSet<>();
addRestResourceClasses(resources);
resources.add(org.glassfish.jersey.Hymanson.HymansonFeature.class);
return resources;
}
/**
* Do not modify addRestResourceClasses() method.
* It is automatically populated with
* all resources defined in the project.
* If required, comment out calling this method in getClasses().
*/
private void addRestResourceClasses(Set<Class<?>> resources) {
resources.add(com.wfscorp.restapitwo.GenericResource.class);
}
}
Then everything worked!
然后一切正常！
Note
笔记
When I used the com.fasterxml.Hymanson.jaxrs dependency I was unable to deploy my application. I started getting a WELD-001408 Unsatisfied dependencies for typeerror so I had to exclude the jersey media multi part.
当我使用 com.fasterxml.Hymanson.jaxrs 依赖项时，我无法部署我的应用程序。我开始收到WELD-001408 Unsatisfied dependencies for type错误，所以我不得不排除球衣媒体多部分。
These are the dependencies in my pom.xml
这些是我的 pom.xml 中的依赖项
<dependencies>
<dependency>
<groupId>org.glassfish.jersey.media</groupId>
<artifactId>jersey-media-json-Hymanson</artifactId>
<version>2.13</version>
<type>jar</type>
</dependency>
<dependency>
<groupId>javax</groupId>
<artifactId>javaee-web-api</artifactId>
<version>7.0</version>
<scope>provided</scope>
</dependency>
<dependency>
<groupId>com.fasterxml.Hymanson.jaxrs</groupId>
<artifactId>Hymanson-jaxrs-json-provider</artifactId>
<version>2.4.0</version>
</dependency>
<dependency>
<groupId>org.glassfish.jersey.media</groupId>
<artifactId>jersey-media-multipart</artifactId>
<version>2.7</version>
<scope>provided</scope>
</dependency>
</dependencies>
回答by Lokesh
This will guide through the entire process Reference ,Simple and Easy - http://examples.javacodegeeks.com/enterprise-java/rest/jersey/json-example-with-jersey-Hymanson/
这将指导整个过程参考，简单易行 - http://examples.javacodegeeks.com/enterprise-java/rest/jersey/json-example-with-jersey-Hymanson/
回答by Scott Johnson
It may be that you need to expose the value property of your Testy object with a getter.
您可能需要使用 getter 公开 Testy 对象的 value 属性。
