Javascript 收到表情符号反应后的 Discord.js 消息

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时间:2020-08-23 04:30:08  来源:igfitidea点击:

Discord.js message after receiving emoji reaction

javascriptdo-whilediscord.js

提问by Ned

It it possible to make a Discord bot send a message once a previous message has received a reaction? I was thinking about something like:

一旦先前的消息收到反应,是否可以让 Discord 机器人发送消息?我在想这样的事情:

if(cmd === `${prefix}list`) {
    var i = 0;

    let embed = new Discord.RichEmbed()
      .addField("List", "Content");

    let anotherembed = new Discord.RichEmbed()
      .addField("Message", "List has been completed!");

    return message.channel.send(embed);

    do {
      message.channel.send(anotherembed + 1);
    }
    while (i !== 0) && (reaction.emoji.name === "?");

}

回答by André

That's not something you should do.
What you want is message.awaitReactions.
There is a great guide by the DiscordJS team and community that has a great example for awaitReactions.
Here is the linkand an example they used:

那不是你应该做的。
你想要的是message.awaitReactions.
DiscordJS 团队和社区有一个很好的指南,其中有一个很好的例子awaitReactions
这是他们使用的链接和示例:

message.react('').then(() => message.react(''));

const filter = (reaction, user) => {
    return ['', ''].includes(reaction.emoji.name) && user.id === message.author.id;
};

message.awaitReactions(filter, { max: 1, time: 60000, errors: ['time'] })
    .then(collected => {
        const reaction = collected.first();

        if (reaction.emoji.name === '') {
            message.reply('you reacted with a thumbs up.');
        }
        else {
            message.reply('you reacted with a thumbs down.');
        }
    })
    .catch(collected => {
        console.log(`After a minute, only ${collected.size} out of 4 reacted.`);
        message.reply('you didn\'t react with neither a thumbs up, nor a thumbs down.');
    });

You basically need a filter, that only allows for a range of emojis, and a user to "use" them.

您基本上需要一个过滤器,它只允许一系列表情符号,以及用户“使用”它们。

And also somewhere on your code you have:

还有你的代码中的某个地方:

return message.channel.send(embed);

You should remove the return part, or else it will just return and don't do the rest of the code.

您应该删除返回部分,否则它只会返回而不执行其余代码。