如何检查数组是否包含 Scala 2.8 中的特定值？
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/3877863/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
How to check that an array contains a particular value in Scala 2.8?
提问by Ivan
I've got an array A of D unique (int, int) tuples.
我有一个由 D 个唯一 (int, int) 元组组成的数组 A。
I need to know if the array contains (X, Y) value.
我需要知道数组是否包含 (X, Y) 值。
Am I to implement a search algorithm myself or there is a standard function for this in Scala 2.8? I've looked at documentationbut couldn't find anything of such there.
我是自己实现搜索算法还是在 Scala 2.8 中有一个标准函数？我查看了文档，但在那里找不到任何此类内容。
回答by huynhjl
That seems easy (unless I'm missing something):
这似乎很容易（除非我遗漏了什么）：
scala> val A = Array((1,2),(3,4))
A: Array[(Int, Int)] = Array((1,2), (3,4))
scala> A contains (1,2)
res0: Boolean = true
scala> A contains (5,6)
res1: Boolean = false
I think the api calls you're looking for is in ArrayLike.
我认为您正在寻找的 api 调用在ArrayLike 中。
回答by Suganthan Madhavan Pillai
I found this nice way of doing
我发现了这种很好的做事方式
scala> var personArray = Array(("Alice", 1), ("Bob", 2), ("Carol", 3))
personArray: Array[(String, Int)] = Array((Alice,1), (Bob,2), (Carol,3))
scala> personArray.find(_ == ("Alice", 1))
res25: Option[(String, Int)] = Some((Alice,1))
scala> personArray.find(_ == ("Alic", 1))
res26: Option[(String, Int)] = None
scala> personArray.find(_ == ("Alic", 1)).getOrElse(("David", 1))
res27: (String, Int) = (David,1)
