PHP 多文件数组
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PHP Multiple File Array
提问by Christopher JB Luck
I have the following code which works and uploads but it will not cycle through the array to upload every file, just the first file.
我有以下代码可以工作和上传，但它不会循环遍历数组来上传每个文件，只是第一个文件。
<form method="post" enctype="multipart/form-data" action="http://<?php echo $pageURL;?>">
<input class="new" multiple="multiple" name="documents[]" type="file" />
<input class="new" multiple="multiple" name="documents[]" type="file" />
<input type="submit" class="button" name="addMaterials" value="Add" />
<?php
foreach($_FILES['documents']['tmp_name'] as $key => $tmp_name)
{
$file_name = $key.$_FILES['documents']['name'][$key];
$file_size =$_FILES['documents']['size'][$key];
$file_tmp =$_FILES['documents']['tmp_name'][$key];
$file_type=$_FILES['documents']['type'][$key];
move_uploaded_file($file_tmp,"files/".time().$file_name);
}
?>
I need it to cycle through my documents[] file array.
我需要它来循环我的文档 [] 文件数组。
Example print_r()of the documents array:
print_r()文档数组示例：
Array (
[name] => Array ( [0] => AcroRd32.exe )
[type] => Array ( [0] => application/x-msdownload )
[tmp_name] => Array ( [0] => C:\xampp\tmp\phpE8BD.tmp )
[error] => Array ( [0] => 0 )
[size] => Array ( [0] => 1343112 )
)
Any help appreciated.
任何帮助表示赞赏。
回答by liyakat
you can use my updated code and as per my demo it is working perfect for multiple file upload
您可以使用我更新的代码，根据我的演示，它非常适合多个文件上传
<?php
if(isset($_FILES['documents'])){
foreach($_FILES['documents']['tmp_name'] as $key => $tmp_name)
{
$file_name = $key.$_FILES['documents']['name'][$key];
$file_size =$_FILES['documents']['size'][$key];
$file_tmp =$_FILES['documents']['tmp_name'][$key];
$file_type=$_FILES['documents']['type'][$key];
move_uploaded_file($file_tmp,"galleries/".time().$file_name);
}
}else{
echo "<form enctype='multipart/form-data' action='test1.php' method='POST'>";
echo "File:<input name='documents[]' multiple='multiple' type='file'/><input type='submit' value='Upload'/>";
echo "</form>";
}
?>
回答by sagits
For anyone trying to do it with a single file php function (i`m using classes, but you can change to a function):
对于尝试使用单个文件 php 函数执行此操作的任何人（我正在使用类，但您可以更改为函数）：
html:
html：
<input type="file" name="foto[]" />
<input type="file" name="foto[]" />
<input type="file" name="foto[]" />
<input type="file" name="foto[]" />
<input type="file" name="foto[]" />
php:
php:
if (isset($_FILES['foto'])) {
$arquivo = array();
foreach ($_FILES['foto']["name"] as $file=>$key) {
// the empty input files create an array index too, so we need to
// check if the name exits. It means the file exists.
if (!empty($_FILES['foto']["name"][$file])) {
$arquivo ["name"] = $_FILES['foto']["name"][$file];
$arquivo ["type"] = $_FILES['foto']["type"][$file];
$arquivo ["tmp_name"] = $_FILES['foto']["tmp_name"][$file];
$arquivo ["error"] = $_FILES['foto']["error"][$file];
$arquivo ["size"] = $_FILES['foto']["size"][$file];
$foto = new foto(); // create an obj foto
// $arquivo means file, it`s our file format as a single $_file['file']
if ($foto -> upload($arquivo)) { // if its uploaded than save
$foto -> save();
}
}
}
}
on my foto class:
在我的照片课上：
public function upload($foto) {
$upload_dir = "D:/xampp/htdocs/prova/fotos/";
$file_dir = $upload_dir . $foto["name"];
$move = move_uploaded_file($foto["tmp_name"], $file_dir);
$this -> arquivo = $foto["name"]; // use this to save to db later
// this serves to return true if the file is uploaded
$retorno = ($move) ? 1 : 0;
return $retorno;
}
回答by sagits
Try with this code for multifile upload
尝试使用此代码进行多文件上传
<form method="post" action="upload-page.php" enctype="multipart/form-data">
<input name="filesToUpload[]" id="filesToUpload" type="file" multiple="" />
</form>
In PHP
在 PHP 中
if(count($_FILES['uploads']['filesToUpload'])) {
foreach ($_FILES['uploads']['filesToUpload'] as $file) {
//do your upload stuff here
echo $file;
}
}
To show the file name using javascript
使用javascript显示文件名
//get the input and UL list
var input = document.getElementById('filesToUpload');
var list = document.getElementById('fileList');
//empty list for now...
while (list.hasChildNodes()) {
list.removeChild(ul.firstChild);
}
//for every file...
for (var x = 0; x < input.files.length; x++) {
//add to list
var li = document.createElement('li');
li.innerHTML = 'File ' + (x + 1) + ': ' + input.files[x].name;
list.append(li);
}
回答by Ranjith
Try this way of loop your documents array()
试试这种循环方式 documents array()
<?php
foreach($_FILES['documents']['tmp_name'] as $key => $tmpName) {
$file_name = $_FILES['documents']['name'][$key];
$file_type = $_FILES['documents']['type'][$key];
$file_size = $_FILES['documents']['size'][$key];
$file_tmp = $_FILES['documents']['tmp_name'][$key];
move_uploaded_file($file_tmp,"files/".time().$file_name);
}
?>
回答by NewCoder
File upload using multiple input fields.
使用多个输入字段上传文件。
HTML
HTML
<form action="" method="post" enctype="multipart/form-data">
<p><input type="file" name="file_array[]"></p>
<p><input type="file" name="file_array[]"></p>
<p><input type="file" name="file_array[]"></p>
<input type="submit" value="Upload all files">
</form>
PHP
PHP
<?php
if(isset($_FILES['file_array'])){
$name_array = $_FILES['file_array']['name'];
$tmp_name_array = $_FILES['file_array']['tmp_name'];
$type_array = $_FILES['file_array']['type'];
$size_array = $_FILES['file_array']['size'];
$error_array = $_FILES['file_array']['error'];
for($i = 0; $i < count($tmp_name_array); $i++){
if(move_uploaded_file($tmp_name_array[$i], "test_uploads/".$name_array[$i])){
echo $name_array[$i]." upload is complete<br>";
} else {
echo "move_uploaded_file function failed for ".$name_array[$i]."<br>";
}
}
}
?>
回答by Rashid Iqbal
it's easy to upload multiple files, follow these steps.
上传多个文件很容易，请按照以下步骤操作。
- use array notation means square brackets with the name of the input like this
<input type="file" id="indtbl_logo[]" name="indtbl_logo[]" multiple />- you can loop throught this using $_FILESGlobal Variable
- 使用数组符号表示方括号与输入的名称是这样的
<input type="file" id="indtbl_logo[]" name="indtbl_logo[]" multiple />- 你可以使用$_FILES全局变量循环遍历这个
foreach ($_FILES['indtbl_logo']['tmp_name'] as $key => $tmp_name) {
$file_name = $key . $_FILES['indtbl_logo']['name'][$key];
$file_size = $_FILES['indtbl_logo']['size'][$key];
$file_tmp = $_FILES['indtbl_logo']['tmp_name'][$key];
$file_type = $_FILES['indtbl_logo']['type'][$key];
echo $file_name;
echo "<br>";
}
